php – 如何使用jquery删除mysql记录

我有以下代码删除mysql记录,我想转换它所以它将是一个ajax / jquery代码,所以我可以保持在从表中删除记录后的同一页面.
现在,它工作正常,但它不在同一页面上,我需要刷新页面才能看到结果.这只是完整代码的一部分.
一页上的所有代码.

//get the mysql results
//this is a repeated region
<tr>
       <td><?php echo $row['id']; ?></td>
       <td><?php echo $row['title']; ?></td>
       <td><?php echo $row['description']; ?></td>
       <td><a href="manage.php?id=<?php echo $row['id']; ?>">Delete</a>
       </td>
</tr>


if ((isset($_GET['deleteid'])) && ($_GET['deleteid'] != "") &&             (isset($_POST['delete']))) {
  $deleteSQL = sprintf("DELETE FROM my_table WHERE id=%s",
                       GetSQLValueString($_GET['deleteid'], "int"));

解决方法:

<tr>
       <td><?php echo $row['id']; ?></td>
       <td><?php echo $row['title']; ?></td>
       <td><?php echo $row['description']; ?></td>
       <td><div class="delete_class" id="<?php echo $row['id']; ?>">Delete</div></td>
</tr>

现在在本节中写下这个

$(document).ready(function(){
 $(".delete_class").click(function(){
   var del_id = $(this).attr('id');
   $.ajax({
      type:'POST',
      url:'delete_page.php',
      data:'delete_id='+del_id,
      success:function(data) {
        if(data) {   // DO SOMETHING
        } else { // DO SOMETHING }
      }
   });
 });
});

现在在’delete_page.php’页面执行此操作

$id = $_POST['delete_id'];
$query = "delete from TABLE NAME where ID = $id";

休息我希望你知道.希望这可以帮助

标签：php,jquery,mysql,ajax,sql-delete
来源： https://codeday.me/bug/20190930/1836076.html