Php Regex查找string是否为mysql select语句
作者:互联网
我正在尝试在执行它们之前验证查询,如果查询不是mysql select语句,那么我必须向用户显示消息.
我从这个链接找到了以下正则表达式:
Validate simple select query using Regular expression
$reg="/^Select\s+(?:\w+\s*(?:(?=from\b)|,\s*))+from\s+\w+\s+where\s+\w+\s*=\s*'[^']*'$/i";
接下来我写下面的代码,但它总是打印不选择查询(每次$match为空)
$string="select * from users where id=1";
preg_match_all($reg,$string,$match);
if(!empty($match)){
echo "select query";
//execute and process result
//$this->user_model->list($string);
}else{
echo "not select query";
//show_message('inv_query');
}
请更正正则表达式以验证sql select语句(select,from,where,join,orderby groupby all in select statement).
或者让我知道完成任务的其他好方法.
/*
some sample select statements
select * from users where id=1;
select * from users where id=1 AND name= 'Prabhu';
select * from users where id=1 AND name= 'Prabhu' order by name;
Select * from users where id=1 AND name= 'Prabhu' group by id order by name;
Select * from users join role on users.role_id=role.id where id=1 AND name= 'Prabhu' group by id order by name;
*/
解决方法:
为什么不喜欢这样的:
$reg = "/^(\s*?)select\s*?.*?\s*?from([\s]|[^;]|(['"].*;.*['"]))*?;\s*?$/i";
适用于SQL select查询示例:http://www.phpliveregex.com/p/6nP.
它还会检查正在运行的唯一SQL查询是否为select查询,因此它应该只验证它们.它通过确保只有一个来做到这一点;除非那个;在一个字符串内,所以下面将验证.
select * from users where id=1 AND name= 'Pra;bhu';
但这不会.
select * from users where id=1 AND name= 'Prabhu'; drop table;
并且没有检查的正则表达式;在一个字符串中,如果它在其中将失败:
$reg = "/^(\s*?)select\s*?.*?\s*?from([\s]|[^;])*?;\s*?$/i"
标签:preg-match-all,php,regex,preg-match 来源: https://codeday.me/bug/20190830/1769293.html