在mysql中使用concat()准备statemnt给出错误
作者:互联网
下面给出的代码是存储过程的一部分(mysql 5.5.20):
prepare stmnt1 from concat('insert into ' , tableName , '(employee_id , administrator_id) values(? , ?) ' ) ;
set @a = 19 ;
set @b = 11;
execute stmnt1 using @a , @b ;
tableName是局部变量
当我创建过程时,我收到此错误:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near 'concat('insert into ' ,
tableName , '(employee_id , administrator_id) values(? ' at line 23
似乎这种语句在mysql中是不可能的.
请帮忙.谢谢.
解决方法:
请试试这个.
set @sql = concat('insert into ' , tableName , '(employee_id , administrator_id) values(? , ?) ' ) ;
prepare stmnt1 from @sql;
set @a = 19 ;
set @b = 11;
execute stmnt1 using @a , @b ;
deallocate prepare stmnt1;
标签:mysql-error-1064,mysql,insert 来源: https://codeday.me/bug/20190826/1727799.html