如何使用存储过程删除mysql数据库中的所有视图？

我希望我的mysql服务器删除数据库中的所有视图.我已经为存储过程创建了一个事件：

开始

DECLARE done INT DEFAULT FALSE; 
DECLARE VIEW_NAME CHAR(255);
DECLARE VIEW_NAMES CURSOR FOR SELECT table_name FROM information_schema.views;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;

OPEN VIEW_NAMES;

read_loop: LOOP    
    FETCH VIEW_NAMES INTO VIEW_NAME;
    IF done THEN
        LEAVE read_loop;
    END IF;    
    DROP VIEW VIEW_NAME;
END LOOP;

CLOSE VIEW_NAMES;

结束

但是,此过程会产生以下错误：

Error Code: 1051. Unknown table ‘view_name’

我的猜测是我的fetch语句由于某种原因没有获取.所以我检查了select语句,它确实有一个结果集.任何有关如何解决错误或如何在mysql数据库中删除所有视图的想法？

解决方法:

您需要使用prepared statements来执行这些查询.构建字符串’DROP VIEW …’,然后使用预准备语句执行语句.

例如 –

...
read_loop: LOOP    
    FETCH VIEW_NAMES INTO VIEW_NAME;
    IF done THEN
        LEAVE read_loop;
    END IF;    

    SET @query = CONCAT('DROP VIEW ', VIEW_NAME);
    PREPARE stmt FROM @query;
    EXECUTE stmt;
    DEALLOCATE PREPARE stmt;

END LOOP;
...

另一个变种,没有打开光标：

SET @views = NULL;

SELECT GROUP_CONCAT(table_schema, '.', table_name) INTO @views
  FROM information_schema.views 
  WHERE table_schema = 'database_name';

SET @views = CONCAT('DROP VIEW ', @views);
PREPARE stmt FROM @views;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

…根据需要修改WHERE条件.

标签：mysql,stored-procedures,sql-view
来源： https://codeday.me/bug/20190826/1725975.html