javascript – 使用node-mysql时的SQL Parse错误

当我尝试使用node-mysql在MYSQL数据库上调用查询时,我遇到了解析错误.我很确定查询有效.毫无疑问,它通过phpmyadmin运行.

Message.save = function(message, callback){
    db.query("INSERT INTO e_message (chatid, message, userid) VALUES(" + message.chatid + ", '" + message.message +"', " + message.userid + "); SELECT * FROM e_message WHERE chatid = " + message.chatid + " ORDER BY timestamp DESC LIMIT 0, 1;", 
    function(err, rows, fields){
        console.log(err);
        callback(err, new Message(rows[0]));
    });
}

我收到了以下错误：

{ [Error: ER_PARSE_ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT * FROM e_message WHERE chatid = 1 ORDER BY timestamp DESC LIMIT 0, 1' at line 1]
  code: 'ER_PARSE_ERROR',
  errno: 1064,
  sqlState: '42000',
  index: 0 }

查询通过console.log()看起来像这样：

INSERT INTO e_message (chatid, message, userid) VALUES(1, 'test123', 1);
SELECT * FROM e_message WHERE chatid = 1 ORDER BY timestamp DESC LIMIT 0, 1;

我不知道这有什么不对……

编辑：
如果我将它分成两个查询,我得到我想要的结果：

Message.save = function(message, callback){
    db.query("INSERT INTO e_message (chatid, message, userid) VALUES(" + message.chatid + ", '" + message.message +"', " + message.userid + ");", function(err, rows, fields){
        db.query("SELECT * FROM e_message WHERE userid = " + message.userid + " AND chatid = " + message.chatid + " ORDER BY timestamp DESC LIMIT 0, 1;", function(err, rows, filds){
            callback(err, new Message(rows[0]));
        });
    });
}

谢谢！

解决方法:

默认情况下,node-mysql不允许您在单个查询中发出多个SQL语句.

为此,您需要在创建连接时设置multipleStatements连接选项.

请注意,允许这样做可能会使您面临SQL注入的风险,尤其是在将语句构建为字符串时.例如,如果您的message.userid设置为字符串1);删除数据库生成; SELECT(,您将遇到麻烦.

在这种情况下,你真正想要的是插入和第二个SELECT LAST_INSERT_ID()来获取插入最新记录的id.它将返回会话的最新插入的自动增量键,也就是说,它不会受到其他连接/会话的其他插入的影响.

标签：javascript,mysql,node-js,node-mysql
来源： https://codeday.me/bug/20190825/1717719.html