delphi TreeView 从数据库添加节点的四种方法
作者：互联网
方法一：delphi中递归算法构建treeView
过程：
通过读取数据库中table1的数据，来构建一颗树。table1有两个字段：ID,preID，即当前结点标志和父结点标志。所以整个树的表示为父母表示法。本递归算法不难写，但是要注意：程序内部的变量都应使用局部变量！比如当Query是外部变量（函数外定义或者直接通过控件拖拽得来）时就会得到错误的结果。代码如下：
unit Unit1;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, DB, ADODB, ComCtrls, StdCtrls;
type
TForm1 = class(TForm)
Button1: TButton;
tree: TTreeView;
Query1: TADOQuery;
procedure Button1Click(Sender: TObject);
procedure CreateTree;
private
{ Private declarations }
public
{ Public declarations }
end;
PTNodeInfo=^TNodeInfo;
TNodeInfo=record
id,preId:string;
end;
var
Form1: TForm1;
implementation
{$R *.dfm}
procedure TForm1.CreateTree;
procedure CreateTree(Pre:string;preNode:TTreeNode);
var
pInfo:PTNodeInfo;
node:TTreeNode;
sql:string;
Query:TADOQUery;
begin
Query:=TADOQuery.Create(nil);
Query.ConnectionString:='Provider=Microsoft.Jet.OLEDB.4.0;Data Source=E:/实验/递归父母表示/新建 Microsoft Office Access 应用程序.mdb;Persist Security Info=False';
sql:= Format('select * from table1 where preId=%s', [QuotedStr(pre)]);
Query.Close;
Query.SQL.Clear;
Query.SQL.Add(sql);
Query.Open;
Query.First;
while not Query.Eof do
begin
new(pInfo);
pInfo.id:=Query.Fields[0].AsString;
pInfo.preId:=Query.Fields[1].AsString;
node:=tree.Items.AddChild(preNode,pInfo.id);
node.Data:=pInfo;
CreateTree(pInfo.id,node);
Query.Next;
end;
Query.Close;
Query.Free;
end;
begin
createTree('000',nil);
tree.FullExpand;
end;
procedure TForm1.Button1Click(Sender: TObject);
begin
createtree;
end;
end.
createTree函数也可以这么写：
procedure TForm1.CreateTree;
var
p:pTNodeInfo;
procedure CreateTree(Pre:PTNodeInfo;preNode:TTreeNode);
var
pInfo:pTNodeInfo;
node:TTreeNode;
sql:string;
Query:TADOQuery;
begin
Query:=TADOQuery.Create(nil);
Query.ConnectionString:='Provider=Microsoft.Jet.OLEDB.4.0;Data Source=E:/实验/递归父母表示/新建 Microsoft Office Access 应用程序.mdb;Persist Security Info=False';
sql:= 'select * from table1';
Query.Close;
Query.SQL.Clear;
Query.SQL.Add(sql);
Query.Open;
Query.First;
while not Query.Eof do
begin
new(pInfo);
pInfo.id:=Query.Fields[0].AsString;
pInfo.preId:=Query.Fields[1].AsString;
if pInfo.preId=pre.id then
begin
node:=tree.Items.AddChild(preNode,pInfo.id);
node.Data:=pInfo;
CreateTree(pInfo,node);
end;
Query.Next;
end;
end;
begin
new(p);
p.id:='000';
createTree(p,nil);
tree.FullExpand;
end;
方法二：//数据采用ADOQuery读取，并将数据暂存在一个动态数组中，树形列表控件为TreeView。
procedure TForm1.LoadTreeInfo;
type
TInfo = record
ID, //代码
Name, //名称
SuperID //上级代码
: string;
//附加字段随需添加
end;
var
sql: string;
i, nCount: Integer;
arrInfo: array of TInfo;
NewNode: TTreeNode;
//加载一个节点
procedure InitOneNode(ANode: TTreeNode; AId: string);
var
k: Integer;
begin
for k := 0 to length(arrInfo) - 1 do
if arrInfo[k].SuperID = AId then
begin
NewNode := TreeView1.Items.AddChild(ANode, arrInfo[k].Name);
InitOneNode(NewNode, arrInfo[k].ID);
end;
end;
begin
TreeView1.Items.BeginUpdate;
TreeView1.Items.Clear;
sql := 'select ID, Name, SuperID from DictionaryTable order by ID';
ADOQuery1.Close;
ADOQuery1.SQL.Text := sql;
ADOQuery1.Open;
nCount := ADOQuery1.RecordCount;
if nCount > 0 then
begin
SetLength(arrInfo, nCount);
for i := 0 to nCount - 1 do
with arrInfo[i] do
begin
ID := Trim(ADOQuery1.FieldByName('ID').AsString);
Name := Trim(ADOQuery1.FieldByName('Name').AsString);
SuperID := Trim(ADOQuery1.FieldByName('SuperID').AsString); //无没有此字段，可根据上下级编码规则赋值
ADOQuery1.Next;
end;
end;
ADOQuery1.Close;
if nCount > 0 then
begin
InitOneNode(nil, ''); //假设顶级代码为空白
TreeView1.FullExpand;
TreeView1.Items.EndUpdate;
end;
end;
方法三： 此方法是第一种方法的变种，凡是有已经添加节点的，删除。
在数据库中建一张表，包含：NodeName,NodeId,ParentId 3个字段，具体什么含义，一看就知了。
过程如下：
procedure TFRM_channel.formtreenode(parentid:string;TreeView1: TTreeView;parentnode:TTreeNode;ADOQuery1:TADOQuery);
var
i:integer;
treenode:TTreeNode;
begin
i:=0;
ADOQuery1.First;
while not ADOQuery1.Eof do
begin
if ADOQuery1.FieldByName('ParentId').AsString=parentid then
begin
treenode:=TreeView1.Items.AddChild(parentnode,ADOQuery1.fieldbyname('NodeName').AsString);
formtreenode(ADOQuery1.fieldbyname('NodeId').AsString ,TreeView1,treenode,ADOQuery1);
end;
inc(i);
ADOQuery1.First;
ADOQuery1.MoveBy(i);
end;
end;
在调用如下，如在窗体的create事件中：
procedure TFRM_channel.FormCreate(Sender: TObject);
var
TreeNode1:TTreeNode;
i:integer;
nodename:string;
nodeid:string;
parentid:string;
cmdstr:string;
begin
//初始化树形节点
ADOQuery1.ConnectionString:=mypublic.datastr;
cmdstr:='select * from ChanTreeNode order by ParentId ,NodeId asc';
ADOQuery1.Close;
ADOQuery1.SQL.Clear;
ADOQuery1.SQL.Add(cmdstr);
ADOQuery1.Open;
TreeNode1:=nil;
formtreenode('000',TreeView1,TreeNode1,ADOQuery1);
end;
方法四：用一个排序的TStringList列表，通过排序列表采用二分查找的快速性能，就能够很快地查找到当前要添加节点的父节点，从而插入到 TreeView树的正确位置。
根据数据表的内容生成TreeView树状结构，通常的做法就是从顶级开始，然后逐项递归查询遍历生成。这种方法在实现上容易做到，也很容易想到，但是效率比较低，因为数据库的检索(SQL语句需要解释执行，而且是对数据库文件进行操作)还是比较耗时的，尤其是树的层次较多，节点较多的情况。这里我要介绍的方法是以空间换取时间，只进行一次数据库检索，提取出全部数据，然后一次生成TreeView树状结构。通过SQL语句，让返回的记录按照父节点ID、节点ID进行排序，这样保证每次当前要添加的节点记录的父节点都已经添加到了TreeView树中，剩下的工作就是如何在TreeView树中找到父节点。这里我采用了一个排序的TStringList列表，通过排序列表采用二分查找的快速性能，就能够很快地查找到当前要添加节点的父节点，从而插入到 TreeView树的正确位置。
源代码如下(假定数据表名称为FTree，字段有ID, ParentID, Name)：
procedure MakeTree(Query: TQuery; TreeView: TTreeView);
var
List: TStringList;
Node: TTreeNode;
Index: Integer;
begin
TreeView.Items.BeginUpdate;
try
TreeView.Items.Clear;
List := TStringList.Create;
try
List.Sorted := True;
while not Query.Eof do
begin
if Query.FieldByName('ParentID').AsInteger = 0 then { ParentID=0，顶层节点 }
Node := TreeView.Items.AddChild(nil, Query.FieldByName('Name').AsString)
else
begin
Index := List.IndexOf(Query.FieldByName('ParentID').AsString);
Node := TreeView.Items.AddChild(TTreeNode(List.Objects[Index]),
Query.FieldByName('Name').AsString);
end;
List.AddObject(Query.FieldByName('ID').AsString, Node);
Query.Next;
end;
finally
List.Free;
end;
finally
TreeView.Items.EndUpdate;
end;
end;
procedure TForm1.Button1Click(Sender: TObject);
var
T: DWORD;
begin
T := GetTickCount;
Query1.SQL.Text := 'SELECT * FROM FTree ORDER BY ParentID, ID';
Query1.Open;
MakeTree(Query1, TreeView1);
Label1.Caption := Format('MakeTree所用时间: %d ms', [GetTickCount - T]);
end;
==============================================================================
unit Unit1;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, StdCtrls, DB, ADODB;
type
PTNode=^TNode;
TNode=record
id:string;
fID,nID:string;
hasCreate:boolean;
fChild:PTNode;
nSibling:PTNode;
end;
type
TArr=array of TNode;
type
TTree=class(TObject)
root,cur:PTNode;
constructor create; overload;
constructor create(var arr:TArr); overload;
function FindNode(s:string;p:PTNode):boolean;
end;
type
TForm1 = class(TForm)
Button1: TButton;
conn: TADOConnection;
Query: TADOQuery;
Memo1: TMemo;
procedure DisPlayFChild(p:PTNode);
procedure LoadData(var arr:Tarr);
function GetNode(var arr:Tarr;s:string):PTNode;
procedure Button1Click(Sender: TObject);
private
{ Private declarations }
public
{ Public declarations }
end;
var
Form1: TForm1;
implementation
{$R *.dfm}
procedure TForm1.displayFChild(p:PTnode);
begin
if p.fChild<>nil then begin memo1.Lines.Add(p.fchild.id); end;
end;
function TTree.FindNode(s:string;p:PTNode):boolean;
var
pn:PTNode;
begin
result:=false;
if p.id=s then
begin
result:=true;
cur:=p;
exit;
end;
pn:=p.fChild;
while ((pn<>nil)and (FindNode(s,pn)=false)) do
begin
pn:=pn.nSibling;
end;
end;
function TForm1.GetNode(var arr:Tarr;s:string):PTNode;
var
i,n:integer;
begin
result:=nil;
n:=Length(arr);
for i:=0 to n-1 do
begin
if (arr[i].id=s) then
begin result:=@arr[i]; exit; end;
end;
end;
procedure TForm1.LoadData(var arr:TArr); //load data from database
var
i:integer;
begin
Query.Close;
Query.SQL.Clear;
Query.SQL.Add('select * from table2');
Query.Open;
Query.First;
i:=Query.RecordCount;
setLength(arr,i);
i:=0;
while not Query.Eof do
begin
arr[i].id:=Query.Fields[0].AsString;
arr[i].fID:=Query.Fields[1].AsString;
arr[i].nID:=Query.Fields[2].AsString;
arr[i].hasCreate:=false;
i:=i+1;
Query.Next;
end;
Query.Close;
end;
constructor TTree.create;
begin
root:=nil;
end;
constructor TTree.create(var arr:TArr); //create a tree from arr
var
i,j,n:integer;
p:PTNode;
begin
i:=0;
n:=Length(arr);
while i<n do
begin
j:=0;
while j<n do
begin
if (arr[j].id='root') and (arr[j].hasCreate=false) then
begin
new(root);
root:=@arr[j];
root.fChild:=nil;
root.nSibling:=nil;
cur:=root;
i:=i+1;
arr[j].hasCreate:=true;
end;
if arr[j].hasCreate=true then
begin
if arr[j].fid<>'none' then
begin
p:=Form1.GetNode(arr,arr[j].fID);
if p.hasCreate=false then
begin
arr[j].fChild:=p;
p.hascreate:=true;
p.fchild:=nil;
p.nsibling:=nil;
i:=i+1;
end;
end;
if arr[j].nid<>'none' then
begin
p:=Form1.GetNode(arr,arr[j].nID);
if p.hascreate=false then
begin
arr[j].nSibling:=p;
p.hascreate:=true;
p.fchild:=nil;
p.nsibling:=nil;
i:=i+1;
end;
end;
end;
j:=j+1;
end;
end;
end;
procedure TForm1.Button1Click(Sender: TObject);
var
arr:TArr;
aTree:TTree;
begin
LoadData(arr);
aTree:=TTree.create(arr);
memo1.Lines.Add(atree.root.fchild.fchild.nsibling.nsibling.id); //test
aTree.Free;
end;
end.
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版权声明：本文为CSDN博主「甜而不腻」的原创文章，遵循CC 4.0 by-sa版权协议，转载请附上原文出处链接及本声明。
原文链接：https://blog.csdn.net/ingener/article/details/78363562
标签：begin,end,delphi,arr,Query,ADOQuery1,TreeView,节点,procedure 来源： https://www.cnblogs.com/jijm123/p/11308063.html