python – SQLite executemany的问题
作者:互联网
我在以下代码中找不到我的错误.当它运行时,为行提供了类型错误:cur.executemany(sql%itr.next())=> ‘函数只需2个参数(给定1个),
import sqlite3
con = sqlite3.connect('test.sqlite')
cur = con.cursor()
cur.execute("create table IF NOT EXISTS fred (dat)")
def newSave(className, fields, objData):
sets = []
itr = iter(objData)
if len(fields) == 1:
sets.append( ':' + fields[0])
else:
for name in fields:
sets.append( ':' + name)
if len(sets)== 1:
colNames = sets[0]
else:
colNames = ', '.join(sets)
sql = " '''insert into %s (%s) values(%%s)'''," % (className, colNames)
print itr.next()
cur.executemany(sql % itr.next())
con.commit()
if __name__=='__main__':
newSave('fred', ['dat'], [{'dat':1}, {'dat':2}, { 'dat':3}, {'dat':4}])
我很感激你的想法.
解决方法:
就像它说的那样,executemany有两个参数.不要使用%自己插入字符串值,而应该传递sql和值,并让db适配器引用它们.
sql = " '''insert into %s (%s) values(%%s)'''," % (className, colNames)
cur.executemany(sql, itr.next())
标签:python,pysqlite 来源: https://codeday.me/bug/20190730/1584648.html