20220817 第一组 于芮 mysql数据库查询(第三十四天)
作者:互联网
# DQL查询语言
## 子查询
按照结果集的行列数不同,子查询可以分为以下几类:
- 标量子查询:结果集只有一行一列(单行子查询)
- 列子查询:结果集有一列多行
- 行子查询:结果集有一行多列
- 表子查询:结果集多行多列
```sql
-- 查询比小虎年龄大的所有学生
-- 标量子查询
SELECT
*
FROM
student
WHERE
age > ( SELECT age FROM student WHERE NAME = '小虎' );
```
```sql
-- 查询有一门学科分数大于90分的学生信息
-- 列子查询
SELECT
*
FROM
student
WHERE
id IN (
SELECT
s_id
FROM
scores
WHERE
score > 90);
```
```sql
-- 查询男生且年龄最大的学生
-- 行子查询
SELECT
*
FROM
student
WHERE
age = (
SELECT
max( age )
FROM
student
GROUP BY
gender
HAVING
gender = '男'
)
-- 优化
SELECT
*
FROM
student
WHERE
( age, gender ) = (
SELECT
max( age ),
gender
FROM
student
GROUP BY
gender
HAVING
gender = '男'
)
```
> 总结:
>
> - where型子查询,如果是where 列 = (内层sql),则内层的sql返回的必须是单行单列,单个值。
> - where型子查询,如果是where (列1,列2) = (内层sql),内层的sql返回的必须是单列,可以是多行。
```sql
-- 取排名数学成绩前五的学生,正序排列
SELECT
*
FROM
(
SELECT
s.*,
sc.score score,
c.NAME 科目
FROM
student s
LEFT JOIN scores sc ON s.id = sc.s_id
LEFT JOIN course c ON c.id = sc.c_id
WHERE
c.NAME = '数学'
ORDER BY
score DESC
LIMIT 5
) t
WHERE
t.gender = '男';
```
> 经验分享:
>
> 1. 分析需求
> 2. 拆步骤
> 3. 分步写sql
> 4. 整合拼装sql
```sql
-- 查询每个老师的代课数
SELECT t.id, t.NAME,( SELECT count(*) FROM course c WHERE c.id = t.id ) AS 代课的数量
FROM
teacher t;
----------------------------------------------------------------------------
SELECT
t.id,
t.NAME,
count(*) '代课的数量'
FROM
teacher t
LEFT JOIN course c ON c.t_id = t.id
GROUP BY
t.id,
t.NAME;
```
```sql
-- exists
SELECT
*
FROM
teacher t
WHERE
EXISTS ( SELECT * FROM course c WHERE c.t_id = t.id );
----------------------------------------------------------------------------SELECT
t.*,
c.`name`
FROM
teacher t
INNER JOIN course c ON t.id = c.t_id;
```
> 总结:如果一个需求可以不用子查询,尽量不使用。
>
> `sql可读性太低。`
除了一些理论知识的学习,今天还有大量的实训案例,来看一下今天的实训成果吧!
-- 1.查询'01'号学生的姓名和各科成绩 ** SELECT s.id sid, s.`name` sname, c.`name` cname, sc.score FROM student s LEFT JOIN scores sc ON s.id = sc.s_id LEFT JOIN course c ON c.id = sc.c_id WHERE s.id = 1; -- 2.查询各个学科的平均成绩和最高成绩** SELECT c.id, c.`name`, AVG( sc.score ), max( sc.score ) FROM course c LEFT JOIN scores sc ON c.id = sc.c_id GROUP BY c.id, c.`name`; -- 3.查询每个同学的最高成绩和科目名称 -- 4.查询所有姓张的同学的各科成绩** SELECT s.id, s.`name`, c.`name` cname, sc.score FROM student s LEFT JOIN scores sc ON sc.s_id = s.id LEFT JOIN course c ON c.id = sc.c_id WHERE s.`name` LIKE '张%'; -- 5.查询每个课程的最高分的学生信息 SELECT * FROM student s WHERE id IN ( SELECT DISTINCT r.s_id FROM ( SELECT c.id, c.NAME, max( score ) score FROM student s LEFT JOIN scores r ON r.s_id = s.id LEFT JOIN course c ON c.id = r.c_id GROUP BY c.id, c.NAME ) t LEFT JOIN scores r ON r.c_id = t.id AND t.score = r.score ); -- 6.查询名字中含有'张'或'李'字的学生的信息和各科成绩。 select student.`name`, scores.`score`, course.`name` FROM student LEFT JOIN scores ON student.id = scores.s_id LEFT JOIN course ON course.id = scores.c_id where student.id = 1 and student.name LIKE '张%' OR student.name LIKE '李%'; -- 7.查询平均成绩及格的同学的信息。 SELECT * FROM student WHERE id IN ( SELECT sc.s_id FROM scores sc GROUP BY sc.s_id HAVING avg( sc.score ) >= 70 ); -- 8.将学生按照总分数进行排名。 SELECT student.id,student.`name`,SUM(scores.score) sum FROM student LEFT JOIN scores on student.id = scores.s_id GROUP BY scores.s_id ORDER BY sum DESC; -- 9.查询数学成绩的最高分、最低分、平均分。 SELECT course.`name`,MAX(scores.score),MIN(scores.score),avg(scores.score) FROM student LEFT JOIN scores ON student.id = scores.s_id LEFT JOIN course ON course.id = scores.c_id WHERE course.NAME = '数学'; -- 10.将各科目按照平均分排序。 SELECT course.`name`,avg(scores.score) avg FROM scores LEFT JOIN course ON course.id = scores.c_id GROUP BY scores.c_id ORDER BY avg DESC; -- 11.查询老师的信息和他所带的科目的平均分 select t.*,c.id,c.name,avg(sc.score) from teacher t left join course c on t.id=c.t_id left join scores sc on sc.c_id=c.id group by t.id,t.name; -- 12.查询被"Tom"和"Jerry"教的课程的最高分和最低分 select t.*,c.name,c.id,max(sc.score),min(sc.score) from teacher t left join course c on t.id=c.t_id left join scores sc on sc.c_id=c.id group by t.id,t.name having t.name in ('Tom','Jerry'); -- 14.查询所有学生的课程及分数 SELECT s.id, s.NAME, c.id, c.NAME, r.score FROM student s LEFT JOIN scores r ON s.id = r.s_id LEFT JOIN course c ON c.id = r.c_id; -- 13.查询每个学生的最好成绩的科目名称 SELECT t.id, t.sname, r.c_id, c.NAME, t.score FROM ( SELECT s.id, s.NAME sname, max( r.score ) score FROM student s LEFT JOIN scores r ON r.s_id = s.id GROUP BY s.id, s.NAME ) t LEFT JOIN scores r ON r.s_id = t.id AND r.score = t.score LEFT JOIN course c ON r.c_id = c.id; -- 15.查询课程编号为1且课程成绩在60分以上的学生的学号和姓名 SELECT * FROM student s WHERE s.id IN ( SELECT r.s_id FROM scores r WHERE r.c_id = 1 AND r.score > 60); SELECT s.*, r.* FROM student s LEFT JOIN scores r ON s.id = r.s_id WHERE r.c_id = 1 AND r.score > 60; -- 16. 查询平均成绩大于等于70的所有学生学号、姓名和平均成绩 select stu.id,stu.name,avg(sc.score) from student stu left join course c on stu.id=c.id left join scores sc on sc.s_id=sc.c_id group by stu.id,stu.name having avg(sc.score)>=70; -- 17.查询有不及格课程的学生信息 select stu.*,c.name,sc.score from student stu left join course c on stu.id=c.id left join scores sc on c.id=sc.c_id where sc.score<60; -- 18.查询每门课程有成绩的学生人数 select count(t.id) ,c.name from ( select c.id,c.name from course c left join scores sc on sc.c_id=c.id where sc.score>0)t left join course c on t.id=c.id group by t.id,t.name; -- 19.查询每门课程的平均成绩,结果按照平均成绩降序排列,如果平均成绩相同,再按照课程编号升序排列 select c.id,c.name,avg(sc.score) from course c left join scores sc on sc.c_id=c.id group by c.id,c.name order by avg(sc.score) desc, c.id asc; -- 20.查询平均成绩大于60分的同学的学生编号和学生姓名和平均成绩 select stu.id,stu.name,avg(sc.score) from student stu left join course c on stu.id=c.id left join scores sc on sc.s_id=sc.c_id group by stu.id,stu.name having avg(sc.score)>60; -- 21.查询有且仅有一门课程成绩在80分以上的学生信息 select stu.id,stu.name from student stu left join scores sc on stu.id =sc.s_id where sc.score>80 group by stu.id,stu.name having count(*)=1; -- 22.查询出只有三门课程的学生的学号和姓名 select stu.id,stu.name from student stu left join scores sc on stu.id =sc.s_id group by stu.id,stu.name having count(*)=3; -- 23.查询有不及格课程的课程信息 select c.id,c.name,sc.score from course c left join scores sc on sc.c_id=c.id group by c.id,c.name having min(sc.score)<60; -- 24.查询至少选择4门课程的学生信息 SELECT s.id, s.NAME FROM student s LEFT JOIN scores r ON s.id = r.s_id GROUP BY s.id, s.NAME HAVING count(*) >= 4; -- 25.查询没有选全所有课程的同学的信息 SELECT * FROM student WHERE id IN ( SELECT r.s_id FROM scores r GROUP BY r.s_id HAVING count(*) != 5 ); -- 26.查询选全所有课程的同学的信息 select stu.* from student stu left join course c on stu.id=c.id group by stu.id,stu.name having (select count(id)from course)=5; -- 27.查询各学生都选了多少门课 select stu.*,count(*) from student stu left join scores sc on stu.id=sc.s_id group by stu.id,stu.name; -- 28.查询课程名称为"java",且分数低于60分的学生姓名和分数 select stu.id,stu.name,sc.score from student stu left join course c on stu.id=c.id left join scores sc on sc.c_id=c.id where c.name='java' and sc.score<60; -- 29.查询学过"Tony"老师授课的同学的信息 select stu.* from student stu left join scores sc on sc.s_id = stu.id left join course c on sc.c_id=c.id left join teacher t on c.t_id=t.id where t.name='Tony'; -- 30.查询没学过"Tony"老师授课的学生信息 SELECT * FROM student WHERE id NOT IN ( SELECT DISTINCT s.id FROM student s LEFT JOIN scores r ON r.s_id = s.id LEFT JOIN course c ON c.id = r.c_id LEFT JOIN teacher t ON t.id = c.t_id WHERE t.NAME = 'Tom' ); -- 1根据学生学号 查询 2020年-1-1之后借过哪些书籍 select stu.sid ,stu.sname,br.bdate from student1 stu left join borrowrecored br on stu.cid=br.cid left join book b on br.bid=b.bid where br.bdate>'2020-1-1'; -- 2根据书籍编号 查询2020-1-1之前都有那哪些学生借阅过 select b.bid,b.bname,br.bdate,stu.sname from book b left join borrowrecored br on b.bid=br.bid left join student stu on br.bid=stu.sid where br.bdate<'2020-1-1'; -- 3根据学生编号查询该生一共借阅过多少本书 select stu.sid,stu.sname,count(*) from student stu left join borrowrecored br on br.bid=stu.sid group by stu.sid,stu.sname; -- 4根据书籍编号查询书籍一共被借阅过多少次 select b.bid,b.bname,count(*) from book b left join borrowrecored br on br.bid=b.bid group by b.bid,b.bname; -- 5根据学院名称查询该学院的学生一共借过哪些书籍 select stu.sdepartment,b.bname,count(*) from student1 stu left join book b on stu.sid=b.bid left join borrowrecored br on b.bid=br.bid group by stu.sdepartment,b.bname; -- 6查询哪个学生最爱看书 select stu.sid,stu.sname ,count(*) from student stu left join book b on stu.sid=b.bid left join borrowrecored br on b.bid=br.bid group by stu.sid order by count(*) desc; -- 7查询那本书最受欢迎 select b.bid,b.bname,count(*) from book b left join borrowrecored br on br.bid=b.bid group by b.bid,b.bname order by count(*) desc
标签:于芮,第三十四,stu,20220817,score,student,scores,sc,id 来源: https://www.cnblogs.com/dijiuzu/p/16596904.html