pgsql或取最新的一条数据

SELECT company.id,company.zz,snap.xydm,snap."companyName", p.xm fr from (
　　SELECT a.id,string_agg(
　　case
　　when d.zzlx = 1 then '路基路面'
　　when d.zzlx = 2 then '桥梁'
　　when d.zzlx = 3 then '隧道'
　　when d.zzlx = 4 then '交通安全设施' end
　　||
　　case
　　when d.zzdj = 1 then '甲级'
　　when d.zzdj = 2 then '乙级'
　　else '' end , ',') as zz
　　from company_info a
　　left join company_info_snapshot b on a.id = b.company_id
　　left join company_aptitude_r c on c.snapshot_id = b.id
　　left join aptitude d on c.aptitude_id = d.id
　　where d.id is not null and a.del_flag = 2 and d.del_flag = 2 and b.del_flag = 2 and zt = 2
　　and concat(a.name,a.xydm) like concat('%','','%')
　　GROUP BY a.id
) company
left join (
　　SELECT company_id,(array_agg(id order by create_time desc ))[1] snapshot_id,
　　(array_agg(name order by create_time desc ))[1] as "companyName",
　　(array_agg(xydm order by create_time desc ))[1] xydm,
　　(array_agg(fddbr order by create_time desc ))[1] fddbr
　　from company_info_snapshot
　　GROUP BY company_id
) snap on snap.company_id = company.id
left join personnel p on p.id = snap.fddbr

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标签：join,agg,company,when,pgsql,最新,或取,snap,id
来源： https://www.cnblogs.com/myself1012/p/16500847.html