leetcode、mysql 175. 组合两个表

表1: Person

+-------------+---------+
| 列名        | 类型     |
+-------------+---------+
| PersonId    | int     |
|  FirstName   | varchar |
| LastName    | varchar |
+-------------+---------+
PersonId 是上表主键
表2: Address

+-------------+---------+
| 列名        | 类型    |
+-------------+---------+
| AddressId   | int     |
| PersonId    | int     |
| City        | varchar |
| State       | varchar |
+-------------+---------+
AddressId 是上表主键
 

编写一个 SQL 查询，满足条件：无论 person 是否有地址信息，都需要基于上述两表提供 person 的以下信息：

答案：
select Person.FirstName, Person.LastName, Address.City, Address.State from Person
left join Address on Person.PersonId = Address.PersonId

标签：varchar,+-------------+---------+,PersonId,mysql,Person,int,Address,175,leetcode
来源： https://blog.csdn.net/m0_61035233/article/details/120103463