编程语言
首页 > 编程语言> > Python-4.21 死锁与递归锁

Python-4.21 死锁与递归锁

作者:互联网

所谓死锁: 是指两个或两个以上的进程或线程在执行过程中,因争夺资源而造成的一种互相等待的现象,若无外力作用,它们都将无法推进下去。此时称系统处于死锁状态或系统产生了死锁,这些永远在互相等待的进程称为死锁进程,如下就是死锁

import time
from threading import Thread, Lock

mutexA = Lock()
mutexB = Lock()


class MyThread(Thread):
    def run(self):
        self.f1()
        self.f2()

    def f1(self):
        mutexA.acquire()
        print('%s 拿到了A锁' % self.name)

        mutexB.acquire()
        print('%s 拿到了B锁' % self.name)
        mutexB.release()

        mutexA.release()

    def f2(self):
        mutexB.acquire()
        print('%s 拿到了B锁' % self.name)
        time.sleep(0.1)

        mutexA.acquire()
        print('%s 拿到了A锁' % self.name)
        mutexA.release()

        mutexB.release()


if __name__ == '__main__':
    for i in range(10):
        t = MyThread()
        t.start()

互斥锁只能acquire一次

from threading import Thread,Lock

mutexA=Lock()

mutexA.acquire()
mutexA.release()

递归锁:可以连续acquire多次,每acquire一次计数器+1,只有计数为0时,才能被抢到acquire

from threading import Thread,RLock
import time

mutexB=mutexA=RLock()

class MyThread(Thread):
    def run(self):
        self.f1()
        self.f2()

    def f1(self):
        mutexA.acquire()
        print('%s 拿到了A锁' %self.name)

        mutexB.acquire()
        print('%s 拿到了B锁' %self.name)
        mutexB.release()

        mutexA.release()


    def f2(self):
        mutexB.acquire()
        print('%s 拿到了B锁' % self.name)
        time.sleep(7)

        mutexA.acquire()
        print('%s 拿到了A锁' % self.name)
        mutexA.release()

        mutexB.release()

if __name__ == '__main__':
    for i in range(10):
        t=MyThread()
        t.start()

标签:name,Python,self,acquire,死锁,mutexA,mutexB,release,4.21
来源: https://blog.csdn.net/weixin_49729516/article/details/113869545