LeetCode题解(1318)：或运算的最小翻转次数(Python)

题目：原题链接（中等）

标签：位运算

解法一：

class Solution:
    def minFlips(self, a: int, b: int, c: int) -> int:
        ans = 0

        length = max(a.bit_length(), b.bit_length(), c.bit_length())
        for i in range(length):
            if c & (1 << i):
                if not a & (1 << i) and not b & (1 << i):
                    ans += 1
            else:
                if a & (1 << i):
                    ans += 1
                if b & (1 << i):
                    ans += 1

        return ans

标签：Python,题解,复杂度,1318,int,length,Ans,bit
来源： https://blog.csdn.net/Changxing_J/article/details/112858701