PageRank算法
作者:互联网
def create(q,graph,N): #compute Probability Matrix L = [[(1-q)/N]*N for i in range(N)] for node,edges in enumerate(graph): num_edge = len(edges) for each in edges: L[each][node] += q/num_edge return L def transform(A): n,m = len(A),len(A[0]) new_A = [[A[j][i] for j in range(n) ] for i in range(m)] return new_A def mul(A,B): n = len(A) m = len(B[0]) B = transform(B) next = [[0]*m for i in range(n)] for i in range(n): row = A[i] for j in range(m): col = B[j] next[i][j] = sum([row[k]*col[k] for k in range(n)]) return next def power(A,N): n = len(A) assert(len(A[0])==n) final_ans,temp = A,A N-=1 while N>0: if N&1: final_ans = mul(final_ans,temp) temp = mul(temp,temp) N >>=1 return final_ans def PageRank(q,graph,N): X = [[1] for i in range(N)] A = create(q,graph,N) X = mul(power(A,20),X) return X print(PageRank(0.85,[[1,2],[2],[0]],3)) ———————————————— 原文链接:https://blog.csdn.net/pp634077956/java/article/details/52604137
穷人版PageRank算法的Python实现
#用于存储图 class Graph(): def __init__(self): self.linked_node_map = {}#邻接表, self.PR_map ={}#存储每个节点的入度 #添加节点 def add_node(self, node_id): if node_id not in self.linked_node_map: self.linked_node_map[node_id] = set({}) self.PR_map[node_id] = 0 else: print("这个节点已经存在") #增加一个从Node1指向node2的边。允许添加新节点 def add_link(self, node1, node2): if node1 not in self.linked_node_map: self.add_node(node1) if node2 not in self.linked_node_map: self.add_node(node2) self.linked_node_map[node1].add(node2)#为node1添加一个邻接节点,表示ndoe2引用了node1 #计算pr def get_PR(self, epoch_num=10, d=0.5):#配置迭代轮数,以及阻尼系数 for i in range(epoch_num): for node in self.PR_map:#遍历每一个节点 self.PR_map[node] = (1-d) + d*sum([self.PR_map[temp_node] for temp_node in self.linked_node_map[node]])#原始版公式 print(self.PR_map) edges = [[1,2], [3,2], [3,5], [1,3], [2,3], [3, 1], [5,1]]#模拟的一个网页链接网络 if __name__ == '__main__': graph = Graph() for edge in edges: graph.add_link(edge[0], edge[1]) graph.get_PR()
原文链接: https://zhuanlan.zhihu.com/p/81691075
2020-05-11
标签:node,map,self,PR,range,算法,PageRank,def 来源: https://www.cnblogs.com/hany-postq473111315/p/12871080.html