javaScript旋转Base64图片并得到新的base64数据
作者:互联网
具体函数的代码就贴在下面了,三个参数
src:图片链接,无论是url地址还是base64数据都可以
edg:旋转角度,注意必须是90°的倍数,否则代码报错,非90°的旋转的根据业务需要裁切裁切,用到的话小伙伴可以动动手修改一下函数
callback:因为img的load是个异步的,所以这才采取回调函数处理load成功的事件,回调的参数就是图片旋转后的base64的数据
function rotateBase64Img(src, edg, callback) { var canvas = document.createElement("canvas"); var ctx = canvas.getContext("2d"); var imgW;//图片宽度 var imgH;//图片高度 var size;//canvas初始大小 if (edg % 90 != 0) { console.error("旋转角度必须是90的倍数!"); throw '旋转角度必须是90的倍数!'; } (edg < 0) && (edg = (edg % 360) + 360) const quadrant = (edg / 90) % 4; //旋转象限 const cutCoor = {sx: 0, sy: 0, ex: 0, ey: 0}; //裁剪坐标 var image = new Image(); image.crossOrigin = "anonymous" image.src = src; image.onload = function () { imgW = image.width; imgH = image.height; size = imgW > imgH ? imgW : imgH; canvas.width = size * 2; canvas.height = size * 2; switch (quadrant) { case 0: cutCoor.sx = size; cutCoor.sy = size; cutCoor.ex = size + imgW; cutCoor.ey = size + imgH; break; case 1: cutCoor.sx = size - imgH; cutCoor.sy = size; cutCoor.ex = size; cutCoor.ey = size + imgW; break; case 2: cutCoor.sx = size - imgW; cutCoor.sy = size - imgH; cutCoor.ex = size; cutCoor.ey = size; break; case 3: cutCoor.sx = size; cutCoor.sy = size - imgW; cutCoor.ex = size + imgH; cutCoor.ey = size + imgW; break; } ctx.translate(size, size); ctx.rotate(edg * Math.PI / 180); ctx.drawImage(image, 0, 0); var imgData = ctx.getImageData(cutCoor.sx, cutCoor.sy, cutCoor.ex, cutCoor.ey); if (quadrant % 2 == 0) { canvas.width = imgW; canvas.height = imgH; } else { canvas.width = imgH; canvas.height = imgW; } ctx.putImageData(imgData, 0, 0); callback(canvas.toDataURL()) }; }
函数略大,不优雅,有什么不合理的地方欢迎小伙伴批评指正,共励共勉。
标签:cutCoor,Base64,edg,base64,canvas,imgH,javaScript,imgW,size 来源: https://www.cnblogs.com/luorende/p/12752686.html