经典算法题--换汽水瓶

“某商店规定：三个空汽水瓶可以换一瓶汽水。小张手上有十个空汽水瓶，她最多可以换多少瓶汽水喝？”答案是5瓶，方法如下：先用9个空瓶子换3瓶汽水，喝掉3瓶满的，喝完以后4个空瓶子，用3个再换一瓶，喝掉这瓶满的，这时候剩2个空瓶子。然后你让老板先借给你一瓶汽水，喝掉这瓶满的，喝完以后用3个空瓶子换一瓶满的还给老板。如果小张手上有n个空汽水瓶，最多可以换多少瓶汽水喝？

Java版

import java.io.BufferedInputStream;
import java.util.Scanner;

public class Glass {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(new BufferedInputStream(System.in));
        while (scanner.hasNext()) {
            int countOriginal = scanner.nextInt();
            if (countOriginal == 0) {
                break;
            }
            System.out.println(countGlass(countOriginal));
        }
    }

    private static int countGlass(int countOriginal) {
        int count = 0;
        while (countOriginal >= 3) {
            int temp = countOriginal / 3;  //计算商
            count += temp;  //兑换的瓶数加上商
            int remainder = countOriginal % 3;  //计算余数
            countOriginal = remainder + temp;  //空瓶数 = 余数 + 商
        }
        if (countOriginal == 2) {
            count += 1;
        }
        return count;
    }
}

标签：count,汽水,个空,int,countOriginal,算法,经典,汽水瓶
来源： https://www.cnblogs.com/fcbyoung/p/12562378.html