面试题03. 数组中重复的数字

• https://leetcode-cn.com/problems/shu-zu-zhong-zhong-fu-de-shu-zi-lcof/

# 法一
# 使用Counter统计，找到重复即可
from collections import Counter
class Solution:
    def findRepeatNumber(self, nums: List[int]) -> int:
        c = Counter(nums)
        return c.most_common()[0][0]

标签：shu,nums,Offer,Python,zhong,Counter,int,版本,重复
来源： https://www.cnblogs.com/cassielcode/p/12469290.html