使用Jackson将json转换为Java对象时如何忽略与Map相关的括号

我正在尝试将JSON转换为Java对象,但是在构建Java等效对象方面遇到了困难.

我的JSON看起来像这样

{
    "point1": {
        "x": 1.0,
        "y": 2.0
    },
    "point2": {
        "x": 1.0,
        "y": 2.0
    },
    "point3": {
        "x": 1.0,
        "y": 2.0
    },
    "customobject1": "cust1",
    "customobject2": "cust2"
}

我需要在这里取点地图,因为将有n个点,

public class Test {

    public String getCustomobject1() {
        return customobject1;
    }

    public void setCustomobject1(String customobject1) {
        this.customobject1 = customobject1;
    }

    public String getCustomobject2() {
        return customobject2;
    }

    public void setCustomobject2(String customobject2) {
        this.customobject2 = customobject2;
    }

    Map<String, Point> testing  = new HashMap<>();

    String customobject1;
    String customobject2; 

    public Map<String, Point> getTesting() {
        return testing;
    }

    public void setTesting(Map<String, Point> testing) {
        this.testing = testing;
    }

}

但是我遇到了无法识别的属性异常,我知道还有一个额外的包装器({})会导致此问题,有人可以建议我在反序列化JSON时如何忽略此映射名称吗？

注意：我正在使用的实际对象具有类似的结构,有点复杂,这里我只是发布一个原型.

解决方法:

如果您事先不知道按键,请使用@JsonAnySetter映射它们：

Marker annotation that can be used to define a non-static, two-argument method (first argument name of property, second value to set), to be used as a “fallback” handler for all otherwise unrecognized properties found from JSON content. It is similar to XmlAnyElement in behavior; and can only be used to denote a single property per type.

If used, all otherwise unmapped key-value pairs from JSON Object values are added to the property (of type Map or bean).

public class Test  {
  private Map<String, Point> points = new HashMap<>();

  @JsonAnySetter
  public void setPoints(String name, Point value) {
    points.put(name, value);
  }

}

标签：jackson-databind,jackson,java
来源： https://codeday.me/bug/20191211/2106001.html