编程语言
首页 > 编程语言> > PHP-下拉列表不会被填充在IE中？

PHP-下拉列表不会被填充在IE中？

作者：互联网

我试图根据类别选择列表中选择的内容将值获取到子类别的选择列表中.它似乎在IE上不起作用.谁能提出这个问题？

在PHP文件中

<body onl oad="setSubcategories(default_value);">

在js文件中,我有类似

 subcategories = new Array();
 subcategories['Lifestyle'] = ['All',
                                  'Beauty (SHC)',
                                  'Skin Care',
                                  'Hair Care',
                                  'Oral Care',
                                  'Cosmetics',
                                  'Footwear',
                                  'Jewelry',
                                  'Male Styling',
                                  'Women Hygiene',
                                  'Womens magazines',
                                  'Apparels',
                                  ' Fashion (AFA)',
                                  'Spa',
                                  'Accessories'
                                  ];
    subcategories['Automobiles'] = ['All',
                           'Automobiles (C&B)',
                           'Cars',
                           'Bikes',
                           'Car Magazine',
                           'Bikes Magazine',
                           'Accessories'
                       ];
    subcategories['FoodandBeverage'] = ['All',
                                  'Snacking',
                                  'Confectionary',
                                  'Beverages',
                                  'Generic F&B',
                                  'Restaurant Review',
                                  'Food Reviews',
                                  'Wines & Vineyards'
                              ];


function setSubcategories(default_value){
    default_value = (typeof default_value == 'undefined') ?
             'All' : default_value;
    var elem = document.getElementById('id-category');
    if(elem == null){return false;}

    var category = elem.value;
    var subelem = document.getElementById('id-subcategory');
    var html = "";
    var subcategoriesArr = subcategories[category];
    for(var i=0; i < subcategoriesArr.length; i++){
        var selected = subcategoriesArr[i] == default_value ? " selected" : "";
        html += '<option' + selected + '>' + subcategoriesArr[i] + '</option>\n';
    }
    subelem.innerHTML = html;
}

解决方法:

尝试使用等效的DOM：

var subcategoriesArr = subcategories[category];
for(var i=0; i < subcategoriesArr.length; i++){
    var option = document.createElement('option');
    option.value = option.text = subcategories[i];
    option.selected = (subcategoriesArr[i] == default_value);
    subelem.appendChild(option);
}

标签：select,drop-down-menu,javascript,php
来源： https://codeday.me/bug/20191210/2101903.html