C#-犀牛-模拟代表
作者:互联网
public interface IServiceInvoker
{
R InvokeService<T, R>(Func<T, R> invokeHandler) where T : class;
}
public class MediaController : Controller
{
private IServiceInvoker _serviceInvoker;
public MediaController(IServiceInvoker serviceInvoker)
{
_serviceInvoker = serviceInvoker;
}
public JsonResult GetAllMedia()
{
var media = _serviceInvoker.InvokeService<IMediaService, List<MediaBase>>(proxy => proxy.GetAllMediaInJson());
JsonResult jsonResult = new JsonResult();
jsonResult.Data = media;
jsonResult.JsonRequestBehavior = JsonRequestBehavior.AllowGet;
return jsonResult;
}
[TestClass]
public class MediaControllerTests
{
[TestMethod]
public void GetAllMedia()
{
JsonResult data;
var serviceInvoker = MockRepository.GenerateStub<IServiceInvoker>();
var media = CreateSeveralMedia();
serviceInvoker.Stub(c => c.InvokeService<IMediaService, List<MediaBase>>(p => p.GetAllMediaInJson())).Return(media);
data = new MediaController(serviceInvoker).GetAllMedia();
serviceInvoker.VerifyAllExpectations();
Assert.IsNotNull(data);
}
}
我正在对服务进行存根并返回集合.当我运行此测试时,media为空.任何想法,我该如何对这个模拟游戏设定期望?
解决方法:
刚刚找到解决方案.看起来有点丑陋,但这是第一次迭代,可能很快才会出现更优雅的版本.该想法是创建另一个存根并匹配Func.反对:
我将为用例提供代码:
[Theory]
[InlineData(342, 31129, 3456)]
public void should_call_service_invoker_and_return_result(int number1, int number2, int expected)
{
var calculator = MockRepository.GenerateStub<ICalculator>();
calculator.Stub(_ => _.Add(number1, number2)).Return(expected);
var serviceInvoker = MockRepository.GenerateStub<ServiceInvoker<ICalculator>>();
serviceInvoker
.Stub(_ => _.Invoke(Arg<Func<ICalculator, int>>.Matches(d => d(calculator) == calculator.Add(number1, number2))))
.Return(expected);
var serviceConsumer = new ServiceConsumer(serviceInvoker);
var actual = serviceConsumer.GetAddResultFor(number1, number2);
Assert.Equal(expected, actual);
}
xUnit扩展用作测试框架.请忽略Theory和InlineData的东西-这是摆脱不必要的测试设置的另一种方法.
这是SUT的代码:
public class ServiceConsumer
{
private readonly ServiceInvoker<ICalculator> serviceInvoker;
public ServiceConsumer(ServiceInvoker<ICalculator> serviceInvoker)
{
this.serviceInvoker = serviceInvoker;
}
public int GetAddResultFor(int number1, int number2)
{
return serviceInvoker.Invoke(_ => _.Add(number1, number2));
}
}
public class ServiceInvoker<T>
{
public virtual R Invoke<R>(Func<T, R> func)
{
throw new NotImplementedException();
}
}
public interface ICalculator
{
int Add(int number1, int number2);
}
希望这会有所帮助.欢迎任何有关增加更多美丽的建议:)
标签:rhino-mocks-3-5,c,rhino-mocks 来源: https://codeday.me/bug/20191208/2092088.html