将VB转换为C#-类型转换

我需要帮助将某些代码从VB转换为C#.

Public Function ToBase36(ByVal IBase36 As Double) As String
    Dim Base36() As String = {"0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"}
    Dim v As String
    Dim i As Decimal
    Do Until IBase36 < 1
        i = IBase36 Mod 36
        v = Base36(i) & v
        IBase36 = Math.DivRem(Long.Parse(IBase36), 36, Nothing)
    Loop
    Return v

End Function

我的问题是VB中类型转换的工作方式,这行给我带来了最大的麻烦,因为IBase36是双精度型,在这种情况下Math.DivRem()应该返回long,而Long.Parse()需要字符串.

IBase36 = Math.DivRem(Long.Parse(IBase36), 36, Nothing)

这是我翻译的工作代码,这要感谢JaredPar和其他人

    public static string ToBase36(double IBase36)
    {
        string[] Base36 = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z" };
        string v = null;
        long i = default(long);
        while (!(IBase36 < 1))
        {
            IBase36 = Convert.ToDouble(Math.DivRem(Convert.ToInt64(IBase36), 36, out i));
            v = Base36[i] + v;
        }
        return v;
    }

解决方法:

要进行翻译,重要的是首先了解VB.Net代码的功能.在引擎盖下,它将基本上产生以下内容

Dim unused As Long
IBase36 = CDbl(Math.DivRem(Long.Parse(CStr(IBase36)), 36, unused)

注意：未使用的变量是必需的,因为第三个参数是out.转换为C#时,这是一个重要的区别.

上面最自然的C#等效项是

long unused;
IBase36 = Convert.ToDouble(Math.DivRem(Long.Parse(IBase36.ToString()), 36, out unused);

标签：implicit-conversion,vb-net,c
来源： https://codeday.me/bug/20191208/2091419.html