Java JApplet：按钮树问题
作者：互联网
此小程序应采用存储在menuTree中的树,并基于该树进行菜单构建.
currentNode存储小程序当前所在的菜单,并且其每个子级都应显示为按钮.
单击按钮后,小程序将带您进入一个新菜单,代表单击的按钮.
我无法让按钮在单击另一个按钮时发生变化.
我不确定这棵树是否正确构建,因为它不是特别容易测试.
任何帮助将不胜感激.
谢谢.
import javax.swing.*;
import javax.swing.tree.*;
import java.awt.event.*;
import java.awt.*;
public class Menu extends JApplet implements ActionListener{
private static final long serialVersionUID = 2142470002L;
private JTree menuTree;
private DefaultMutableTreeNode currentNode;
private JPanel buttonPanel;
public void init(){
this.setSize(700, 550);
buttonPanel=new JPanel();
buttonPanel.setSize(300, 500);
this.add(buttonPanel);
/**
* will make node out of the first entry in the array, then make nodes out of subsequent entries
* and make them child nodes of the first one. The process is repeated recursively for entries that are arrays.
* this idea of tree declaration as well as the code from the method was lovingly
* stolen from: http://www.apl.jhu.edu/~hall/java/Swing-Tutorial/Swing-Tutorial-JTree.html
*/
Object [] menuNames = { "ROOT",
new Object[] { "Classic Chess",
new Object[] { "Game",
"AI",
"Hotseat",
"Online"
},
"Challenges",
new Object[]{ "Practice",
"Situations",
"Coaching"
},
},
new Object[] { "Fairy Chess",
new Object[] { "Game",
"AI",
"Hotseat",
"Online"
},
"Challenges",
new Object[]{ "Practice",
"Situations",
"Coaching"
},
"Create Pieces"
}
};
currentNode=processHierarchy(menuNames);
menuTree = new JTree(currentNode);
initializeButtons(currentNode);
}
/**
* Clicking one of the buttons(which should be in the children of the currentNode), takes you to that node in the tree
* setting currentNode to that node and redoing buttons to represent its children.
*/
public void actionPerformed(ActionEvent ae){
Button b=(Button)ae.getSource();
for(int i =0; i<currentNode.getChildCount(); i++){
if(b.getLabel().equals(currentNode.getChildAt(i)+"")){
currentNode=(DefaultMutableTreeNode)currentNode.getChildAt(i);
initializeButtons(currentNode);
}
}
}
/**
* will make node out of the first entry in the array, then make nodes out of subsequent entries
* and make them child nodes of the first one. The process is repeated recursively for entries that are arrays.
* this idea of tree declaration as well as the code from the method was lovingly
* stolen from: http://www.apl.jhu.edu/~hall/java/Swing-Tutorial/Swing-Tutorial-JTree.html
*/
private DefaultMutableTreeNode processHierarchy(Object[] hierarchy) {
DefaultMutableTreeNode node = new DefaultMutableTreeNode(hierarchy[0]);
DefaultMutableTreeNode child;
for (int i = 1; i < hierarchy.length; i++) {
Object nodeSpecifier = hierarchy[i];
if (nodeSpecifier instanceof Object[]) // Ie node with children
child = processHierarchy((Object[]) nodeSpecifier);
else
child = new DefaultMutableTreeNode(nodeSpecifier); // Ie Leaf
node.add(child);
}
return (node);
}
/**
* creates buttons for each child of the given node, labels them with their String value, and adds them to the panel.
*/
private void initializeButtons(DefaultMutableTreeNode node){
Button b;
buttonPanel.removeAll();
for(int i =0; i<node.getChildCount(); i++){
b=new Button();
b.setLabel(""+node.getChildAt(i));
buttonPanel.add(b);
}
}
}
解决方法:
遵循@Andrew的有用概述,TreeSelectionListener似乎很合适.有关详细信息,请参见How to Use Trees.应用程序似乎更容易调试.使用revalidate()是更新修订版式的关键.
import java.awt.BorderLayout;
import java.awt.Button;
import java.awt.Container;
import java.awt.EventQueue;
import java.awt.GridLayout;
import javax.swing.JApplet;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JScrollPane;
import javax.swing.JTree;
import javax.swing.event.TreeSelectionEvent;
import javax.swing.event.TreeSelectionListener;
import javax.swing.tree.DefaultMutableTreeNode;
/** @see https://stackoverflow.com/questions/7342713 */
public class Menu extends JApplet {
private JTree menuTree;
private JPanel buttonPanel;
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
JFrame frame = new JFrame();
frame.setTitle("Menu");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
new Menu().initContainer(frame);
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
@Override
public void init() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
initContainer(Menu.this);
}
});
}
private void initContainer(Container container) {
container.setLayout(new GridLayout(1, 0));
buttonPanel = new JPanel(new GridLayout(0, 1));
Object[] menuNames = {"ROOT",
new Object[]{"Classic Chess",
new Object[]{"Game", "AI", "Hotseat", "Online"},
"Challenges",
new Object[]{"Practice", "Situations", "Coaching"}
},
new Object[]{"Fairy Chess",
new Object[]{"Game", "AI", "Hotseat", "Online"},
"Challenges",
new Object[]{"Practice", "Situations", "Coaching"},
"Create Pieces"
}
};
DefaultMutableTreeNode currentNode = processHierarchy(menuNames);
menuTree = new JTree(currentNode);
menuTree.setVisibleRowCount(10);
menuTree.expandRow(2);
initializeButtons(currentNode);
container.add(buttonPanel, BorderLayout.WEST);
container.add(new JScrollPane(menuTree), BorderLayout.EAST);
menuTree.addTreeSelectionListener(new TreeSelectionListener() {
@Override
public void valueChanged(TreeSelectionEvent e) {
initializeButtons((DefaultMutableTreeNode)
menuTree.getLastSelectedPathComponent());
}
});
}
private DefaultMutableTreeNode processHierarchy(Object[] hierarchy) {
DefaultMutableTreeNode node = new DefaultMutableTreeNode(hierarchy[0]);
DefaultMutableTreeNode child;
for (int i = 1; i < hierarchy.length; i++) {
Object nodeSpecifier = hierarchy[i];
if (nodeSpecifier instanceof Object[]) {
child = processHierarchy((Object[]) nodeSpecifier);
} else {
child = new DefaultMutableTreeNode(nodeSpecifier);
}
node.add(child);
}
return (node);
}
private void initializeButtons(DefaultMutableTreeNode node) {
Button b;
buttonPanel.removeAll();
for (int i = 0; i < node.getChildCount(); i++) {
b = new Button();
b.setLabel("" + node.getChildAt(i));
buttonPanel.add(b);
buttonPanel.revalidate();
}
}
}
标签：jtree,japplet,button,swing,java 来源： https://codeday.me/bug/20191208/2087856.html