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python-使用QtDesigner的pyQt信号/插槽

作者:互联网

我正在尝试编写一个将与QGraphicsView交互的程序.我想在QGraphicsView中收集鼠标和键盘事件.例如,如果用户单击QGraphicsView小部件,我将获得鼠标位置,类似这样.我可以很容易地对其进行硬编码,但是我想使用QtDesigner,因为UI会经常更改.

这是我为gui.py提供的代码.一个带有QGraphicsView的简单小部件.

from PyQt4 import QtCore, QtGui

try:
    _fromUtf8 = QtCore.QString.fromUtf8
except AttributeError:
    _fromUtf8 = lambda s: s

class Ui_graphicsViewWidget(object):
    def setupUi(self, graphicsViewWidget):
        graphicsViewWidget.setObjectName(_fromUtf8("graphicsViewWidget"))
        graphicsViewWidget.resize(400, 300)
        graphicsViewWidget.setMouseTracking(True)
        self.graphicsView = QtGui.QGraphicsView(graphicsViewWidget)
        self.graphicsView.setGeometry(QtCore.QRect(70, 40, 256, 192))
        self.graphicsView.setObjectName(_fromUtf8("graphicsView"))

        self.retranslateUi(graphicsViewWidget)
        QtCore.QMetaObject.connectSlotsByName(graphicsViewWidget)

    def retranslateUi(self, graphicsViewWidget):
        graphicsViewWidget.setWindowTitle(QtGui.QApplication.translate("graphicsViewWidget", "Form", None, QtGui.QApplication.UnicodeUTF8))

该程序的代码:

#!/usr/bin/python -d

import sys
from PyQt4 import QtCore, QtGui
from gui import Ui_graphicsViewWidget

class MyForm(QtGui.QMainWindow):

    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
        self.ui = Ui_graphicsViewWidget()
        self.ui.setupUi(self)
        QtCore.QObject.connect(self.ui.graphicsView, QtCore.SIGNAL("moved"), self.test)

    def mouseMoveEvent(self, event):
        print "Mouse Pointer is currently hovering at: ", event.pos()
        self.emit(QtCore.SIGNAL("moved"), event)

    def test(self, event):
        print('in test')

if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    myapp = MyForm()
    myapp.show()
    sys.exit(app.exec_())

当我运行这段代码时,它给了我与我想要的相反的东西.除了在QGraphicsView内部,我到处都可以看到鼠标的位置.

我确定这是我的QObject.connect的问题.但是每次我回过头来阅读有关信号和插槽的信息时,这都是有道理的,但我却听不懂.

请帮忙,这几天来我一直在head头.很抱歉,是否如以前所要求的那样,但是我已经遍历了有关此主题的所有主题,因此无处可寻.

谢谢

解决方法:

信号必须来自ui中定义的QGraphicsView对象.

您可以像这样从QGraphicsView派生一个类

from PyQt4.QtCore import *
from PyQt4.QtGui import *

class MyView(QGraphicsView):
    moved = pyqtSignal(QMouseEvent)

    def __init__(self, parent = None):
        super(MyView, self).__init__(parent)

    def mouseMoveEvent(self, event):
        # call the base method to be sure the events are forwarded to the scene
        super(MyView, self).mouseMoveEvent(event)

        print "Mouse Pointer is currently hovering at: ", event.pos()
        self.moved.emit(event)

然后,在设计器中:

>右键单击QGraphicsView,然后升级到
>在“晋升的班级名称”字段中输入班级名称(例如“ MyView”),
>在“头文件”字段中输入该类的文件名,但不带.py扩展名,
>单击添加按钮,然后单击升级按钮.

您可以使用pyuic4重新生成文件gui.py.

标签:qt-designer,slots,pyqt4,python,signals
来源: https://codeday.me/bug/20191207/2087393.html