java-方括号内的单词-RegExp

String linkPattern = "\\[[A-Za-z_0-9]+\\]";  
String text = "[build]/directory/[something]/[build]/";   
RegExp reg = RegExp.compile(linkPattern,"g");  
MatchResult matchResult = reg.exec(text);  
for (int i = 0; i < matchResult.getGroupCount(); i++) {  
    System.out.println("group" + i + "=" + matchResult.getGroup(i));  
} 

我正在尝试将所有由正方形bracets封装的块形成一个路径字符串：
而我只得到group0 =“ [build]”我想要的是：
1：“ [build]” 2：“ [something]” 3：“ [build]”

编辑：
只是为了清楚起见,方括号内的单词是用随机文本生成的

public static String genText()
{
    final int LENGTH = (int)(Math.random()*12)+4;

    StringBuffer sb = new StringBuffer();
    for (int x = 0; x < LENGTH; x++)
    {
        sb.append((char)((int)(Math.random() * 26) + 97));
    }
    String str = sb.toString();
    str = str.substring(0,1).toUpperCase() + str.substring(1);
    return str;
}

编辑2：
JDK工作正常,GWT RegExp出现此问题

解决了：
Didier L的回答

String linkPattern = "\\[[A-Za-z_0-9]+\\]";
    String result = "";
String text = "[build]/directory/[something]/[build]/";
RegExp reg = RegExp.compile(linkPattern,"g");
MatchResult matchResult = null;
while((matchResult=reg.exec(text)) != null){
    if(matchResult.getGroupCount()==1) 
        System.out.println( matchResult.getGroup(0));
}

解决方法:

我不知道您正在使用哪个正则表达式库,但是使用JDK中的一个正则表达式库

String linkPattern = "\\[[A-Za-z_0-9]+\\]";
String text = "[build]/directory/[something]/[build]/";
Pattern pat = Pattern.compile(linkPattern);
Matcher mat = pat.matcher(text);
while (mat.find()) {
    System.out.println(mat.group());
}

输出：

[build]
[something]
[build]

标签：java,gwt,regex
来源： https://codeday.me/bug/20191201/2083066.html