验证电子邮件格式PHP

这是用户邀请代码的片段.该代码应从先前的POST表单中获取电子邮件地址,然后检查其格式是否正确.我使用了一个名为checkMail的功能来完成这项工作.但是,似乎无论何时电子邮件格式错误或表单为空白时,它都不会显示以下行：

else if(checkEmail($_POST['email'])==false){ 'Whoops! Looks like the email address you selected is invalid :('; }

要么

else { 'Whoops! It looks like you didn't actually add an email address...'; }

已经被困了几个小时,试图调试…希望这里有人可以帮助我！

这是完整的代码：

if(!empty($_POST['email'])) {
        if(checkEmail($_POST['email'])==true) {
            $thisDomain = str_replace('www.', '', $_SERVER['HTTP_HOST']);
            $mailcont = "Someone has invited you to an invite only website!\nYour invite code is: ".$_POST['code'].".\n\nYou can use it at http://".$thisDomain."?go=register&hash=".$_POST['code'];
            if(sendEmail($_POST['email'],'You have been invited!',$mailcont,'noreply@'.$thisDomain)) {
                echo 'Your invite was dispatched to '.$_POST['email'].'<br /><br />Go back <a href="?go=home">home</a>';
            } else { echo 'Whoops! Something went horribly wrong, and we couldn&#39;t send the email :('; }
        } else if(checkEmail($_POST['email'])==false){ 'Whoops! Looks like the email address you selected is invalid :('; }
    } else { 'Whoops! It looks like you didn&#39;t actually add an email address...'; }
break;

这是功能checkMail的代码：

function checkEmail($email) 
   /**
Validate an email address.
Provide email address (raw input)
Returns true if the email address has the email 
address format and the domain exists.
*/
{
   $isValid = true;
   $atIndex = strrpos($email, "@");
   if (is_bool($atIndex) && !$atIndex)
   {
      $isValid = false;
   }
   else
   {
      $domain = substr($email, $atIndex+1);
      $local = substr($email, 0, $atIndex);
      $localLen = strlen($local);
      $domainLen = strlen($domain);
      if ($localLen < 1 || $localLen > 64)
      {
         // local part length exceeded
         $isValid = false;
      }
      else if ($domainLen < 1 || $domainLen > 255)
      {
         // domain part length exceeded
         $isValid = false;
      }
      else if ($local[0] == '.' || $local[$localLen-1] == '.')
      {
         // local part starts or ends with '.'
         $isValid = false;
      }
      else if (preg_match('/\\.\\./', $local))
      {
         // local part has two consecutive dots
         $isValid = false;
      }
      else if (!preg_match('/^[A-Za-z0-9\\-\\.]+$/', $domain))
      {
         // character not valid in domain part
         $isValid = false;
      }
      else if (preg_match('/\\.\\./', $domain))
      {
         // domain part has two consecutive dots
         $isValid = false;
      }
      else if
(!preg_match('/^(\\\\.|[A-Za-z0-9!#%&`_=\\/$\'*+?^{}|~.-])+$/',
                 str_replace("\\\\","",$local)))
      {
         // character not valid in local part unless 
         // local part is quoted
         if (!preg_match('/^"(\\\\"|[^"])+"$/',
             str_replace("\\\\","",$local)))
         {
            $isValid = false;
         }
      }
      if ($isValid && !(checkdnsrr($domain,"MX") || 
 checkdnsrr($domain,"A")))
      {
         // domain not found in DNS
         $isValid = false;
      }
   }
   return $isValid;
}

在此先感谢大家.你们真棒,我是Stackoverflow的新手,但我发现自己每天都回到这里来寻求想法和社区的大力帮助！

解决方法:

否则{‘哇！看来您实际上并未添加电子邮件地址…’; }
应该
否则{echo’Whoops！看来您实际上并未添加电子邮件地址…’; }

标签：verification,email,mysql,php
来源： https://codeday.me/bug/20191201/2078447.html