php-可捕获的致命错误:传递给(…)的参数1必须是给定()整数的实例
作者:互联网
我正在制作固定装置,尝试加载它们时出现错误.我需要一个Movie对象的实例,但是我给出的(我不知道为什么)是整数.因此,它告诉我出现以下错误:
[Symfony\Component\Debug\Exception\ContextErrorException]
Catchable Fatal Error: Argument 1 passed to Filmboot\MovieBundle\Document\A
ward::setMovie() must be an instance of Filmboot\MovieBundle\Document\Movie
, integer given, called in C:\Programming\xampp\htdocs\filmboot.web\src\Fil
mboot\MovieBundle\DataFixtures\MongoDB\Awards.php on line 143 and defined i
n C:\Programming\xampp\htdocs\filmboot.web\src\Filmboot\MovieBundle\Documen
t\Award.php line 107
这是我的夹具类:
namespace Filmboot\MovieBundle\DataFixtures\MongoDB;
use Doctrine\Common\DataFixtures\AbstractFixture;
use Doctrine\Common\DataFixtures\OrderedFixtureInterface;
use Doctrine\Common\Persistence\ObjectManager;
use Filmboot\MovieBundle\Document\Award;
class Awards extends AbstractFixture implements OrderedFixtureInterface {
public function load(ObjectManager $manager) {
$awards = array(
array(
"name" => "Sitges",
"year" => "1992",
"category" => "Best director"
);
foreach ($awards as $award) {
$document = new Award();
$document->setName ($award["name"]);
$document->setYear ($award["year"]);
$document->setCategory($award["category"]);
$manager->persist($document);
$this->addReference("award-" .$i, $award);
}
$manager->flush();
}
public function getOrder() {
return 1;
}
}
这是文档类:
namespace Filmboot\MovieBundle\Document;
use Doctrine\ODM\MongoDB\Mapping\Annotations as ODM;
use Doctrine\Common\Collections\ArrayCollection;
use Filmboot\MovieBundle\Util;
/**
* @ODM\Document(db="filmbootdb", collection="awards")
* @ODM\Document(repositoryClass="Filmboot\MovieBundle\Document\AwardRepository")
*/
class Award {
/**
* @ODM\Id
*/
private $id;
/**
* @ODM\String
*/
private $name;
/**
* @ODM\Int
*/
private $year;
/**
* @ODM\String
*/
private $category;
/**
* @ODM\ReferenceOne(targetDocument="Movie", mappedBy="awards", cascade={"persist"})
*/
private $movie;
public function getId() {
return $this->id;
}
public function setName($name) {
return $this->name = $name;
}
public function getName() {
return $this->name;
}
public function setYear($year) {
return $this->year = $year;
}
public function getYear() {
return $this->year;
}
public function setCategory($category) {
return $this->category = $category;
}
public function getCategory() {
return $this->category;
}
public function setMovie(\Filmboot\MovieBundle\Document\Movie $movie) {
$movie->setAward($this);
return $this->movie = $movie;
}
}
解决方法:
如我们所见,您明确为电影指定了一个整数:
$awards = array(
array(
// ...
"movie" => 1,
),
);
// ...
$document->setMovie ($award["movie"]);
脚本而不是电影对象会崩溃,因为它需要一个电影对象:
public function setMovie(\Filmboot\MovieBundle\Document\Movie $movie) {
return $this->movie = $movie;
}
因此,解决方案是创建电影的固定装置,并将其设置为reference:
// When saving inside Movie fixtures
$manager->persist($movie);
$manager->flush();
$this->addReference('movie-'.$i, $movie); // Give the references as movie-1, movie-2...
然后首先使用getOrder()方法加载它们:
public function getOrder()
{
return 0; // 0, loaded first
}
控制在电影之后加载奖项:
public function getOrder()
{
return 1; // loaded after 0...
}
然后在您的Award灯具中通过引用检索它们之后,它将加载整个对象,而不仅仅是id(整数):
$awards = array(
array(
// ...
"movie" => $this->getReference('movie-1'), // Get the Movie object, not just id
),
);
// ...
$document->setMovie ($award["movie"]);
请注意,如果要使用参考和订单,则灯具类需要实现OrderedFixtureInterface:
namespace Acme\HelloBundle\DataFixtures\ORM;
use Doctrine\Common\DataFixtures\AbstractFixture;
use Doctrine\Common\DataFixtures\OrderedFixtureInterface;
use Doctrine\Common\Persistence\ObjectManager;
use Acme\HelloBundle\Entity\Group;
class LoadGroupData extends AbstractFixture implements OrderedFixtureInterface
您必须对所有其他实体(例如演员,导演)执行此操作.
您可以找到在夹具here之间共享对象(通过参考)的文档.
编辑:
使双向工作,适应奖项制定者:
public function setMovie(\Filmboot\MovieBundle\Document\Movie $movie) {
$movie->setAward($this);
return $this->movie = $movie;
}
并使用级联持久性来适应持久性:
/**
* @ODM\ReferenceOne(targetDocument="Movie", mappedBy="awards", cascade={"persist"})
*/
private $movie;
标签:fixtures,mongodb,symfony,orm,php 来源: https://codeday.me/bug/20191122/2060376.html