JavaScript-第0行的Google可视化-无效行类型
作者:互联网
我必须使用Google可视化来可视化饼图上的url json数据.我的代码似乎已达到目的,但是在控制台中出现“行0的行类型无效”错误.数据格式是否有问题?如果有人可以提供帮助,将不胜感激.这是我的代码:
PHP:
<?php
$json = file_get_contents('http://data.police.uk/api/crimes-street/all-crime?lat=52.629729&lng=-1.131592&date=2013-01');
$json = str_replace("\xe2\x80\xa8", '\\u2028', $json);
$json = str_replace("\xe2\x80\xa9", '\\u2029', $json);
echo $json;
?>
JavaScript:
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript">
// Load the Visualization API and the piechart package.
google.load('visualization', '1', {'packages':['corechart']});
// Set a callback to run when the Google Visualization API is loaded.
google.setOnLoadCallback(drawChart);
function drawChart() {
var jsonData = $.ajax({
url: "getData.php",
dataType:"json",
async: false
}).responseText;
//Create an array of the JSON data and then create our data table out of JSON data loaded from server.
var array = JSON.parse(jsonData);
var dataTableData = new google.visualization.arrayToDataTable(array);
var table = google.visualization.DataTable(dataTableData);
var chart = new google.visualization.PieChart(document.getElementById('chart_div'));
chart.draw(data, {width: 400, height: 240});
}
</script>
</head>
<body>
<div id="chart_div"></div>
</body>
谢谢.
解决方法:
> JSON不代表可以转换为二维数组google.visualization.DataTable的数据,因此无法解释该数据.每个项目都包含复杂的子项目,例如location和result_status.
>您必须包括列-arrayToDataTable is very specific about that.
>最重要的:您如何想象这些数据以饼图的形式呈现?第一层只有一个特定的数字字段location_subtype.您不能基于各种字符串生成饼图.
但是,您可以清理数据并将其显示为google.visualization.Table:
首先用一些列创建一个DataTable:
var dataTable = new google.visualization.DataTable();
dataTable.addColumn('string','category');
dataTable.addColumn('string','context');
dataTable.addColumn('string','id');
dataTable.addColumn('number','location_subtype');
dataTable.addColumn('string','location_type');
dataTable.addColumn('string','month');
dataTable.addColumn('string','persistent_id');
将您的jsonData转换为JSON
var json=JSON.parse(jsonData);
清理并插入数据.在这里,我只是删除location和result_status子项,但是您可能想从这些子项中提取值,并将其作为列插入dataTable中:
for (var i=0;i<json.length;i++) {
delete json[i].location;
delete json[i].outcome_status;
var row = [];
for (var item in json[i]) {
row.push(json[i][item]);
}
dataTable.addRow(row);
}
最后创建Table():
var chart = new google.visualization.Table(document.getElementById('chart_div'));
chart.draw(dataTable, {width: 1000, height: 300});
结果将如下所示:
更新
var dataTable = new google.visualization.DataTable();
dataTable.addColumn('string','category');
dataTable.addColumn('string','context');
dataTable.addColumn('number','id');
dataTable.addColumn('string','location_subtype');
dataTable.addColumn('string','location_type');
dataTable.addColumn('string','month');
dataTable.addColumn('string','persistent_id');
dataTable.addColumn('string','street name');
dataTable.addColumn('string','outcome status');
json=JSON.parse(jsonData);
for (var i=0;i<json.length;i++) {
var row = [];
row.push(json[i].category);
row.push(json[i].context);
row.push(json[i].id);
row.push(json[i].location_subtype);
row.push(json[i].location_type);
row.push(json[i].month);
row.push(json[i].persistent_id);
row.push(json[i].location.street.name);
row.push(json[i].outcome_status ? json[i].outcome_status.category : "null");
dataTable.addRow(row);
}
标签:google-visualization,javascript,php 来源: https://codeday.me/bug/20191122/2057878.html