java-Hibernate 4.3.6和Glassfish 4.0 JPA 2.1对象不是声明类的实例
作者:互联网
我的ejb项目使用的是Hibernate 4.3.6和Glassfish 4.0.
我的考试道课:
@PersistenceContext
private EntityManager entityManager;
public void saveTest(){
Foo testFoo = new Foo();
testFoo.setSomething("test");
entityManager.persist(testFoo);
entityManager.flush();
}
和POJO类Foo.class:
@Entity
@Table(name = "FOO")
public class Foo implements Serializable {
private static final long serialVersionUID = 1L;
private Long id;
private String something;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "T_ID", unique = true, nullable = false, precision = 15, scale = 0)
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
@Column(name = "T_SOMETHING", length = 50)
public String getSomething() {
return something;
}
public void setSomething(String something) {
this.adi = something;
}
}
persistence.xml:
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence
http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd"
version="2.1">
<persistence-unit name="TestAppUnit" transaction-type="JTA">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<jta-data-source>jdbc/TestApp</jta-data-source>
<class>com.example.test.Foo</class>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<property name="hibernate.transaction.jta.platform"
value="org.hibernate.service.jta.platform.internal.SunOneJtaPlatform" />
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9iDialect" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.format_sql" value="true" />
</properties>
</persistence-unit>
</persistence>
我可以列出表数据,通过查询获取数据,也可以从表中删除数据.但是我不能坚持或合并.
例外是:
IllegalArgumentException occurred calling getter of com.example.test.Foo.id
at org.hibernate.property.BasicPropertyAccessor$BasicGetter.get(BasicPropertyAccessor.java:192)
at org.hibernate.tuple.entity.AbstractEntityTuplizer.getIdentifier(AbstractEntityTuplizer.java:346)
at org.hibernate.persister.entity.AbstractEntityPersister.getIdentifier(AbstractEntityPersister.java:4746)
at org.hibernate.persister.entity.AbstractEntityPersister.isTransient(AbstractEntityPersister.java:4465)
at org.hibernate.engine.internal.ForeignKeys.isTransient(ForeignKeys.java:243)
at org.hibernate.event.internal.AbstractSaveEventListener.getEntityState(AbstractSaveEventListener.java:511)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.performSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:100)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:90)
at org.hibernate.internal.SessionImpl.fireSaveOrUpdate(SessionImpl.java:684)
at org.hibernate.internal.SessionImpl.saveOrUpdate(SessionImpl.java:676)
at org.hibernate.internal.SessionImpl.saveOrUpdate(SessionImpl.java:671)
....
Caused by: java.lang.IllegalArgumentException: object is not an instance of declaring class
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:601)
at org.hibernate.property.BasicPropertyAccessor$BasicGetter.get(BasicPropertyAccessor.java:169)
我在哪里做错了?
此项目在具有persistence.xml版本1.0(jpa)且没有此行的Glassfish 3.1上工作:
<property name="hibernate.transaction.jta.platform"
value="org.hibernate.service.jta.platform.internal.SunOneJtaPlatform" />
提前致谢
解决方法:
我找到了.也许其他人遇到了这个问题.我想分享解决方案.
由Hibernate和“ @PersistenceContext”注释引起的问题.
我将Hibernate版本更改为4.3.5,问题已解决. Hibernate 4.3.6和4.3.7有相同的问题.这是由不同的类加载器引起的. Ejb Classloader和Web应用程序Classloader是不同的.
标签:glassfish-4,jpa,hibernate,java 来源: https://codeday.me/bug/20191121/2049222.html