如何在mongoengine python中聚合组

我正在尝试在MongoDB中汇总组.

我们正在使用Python,django,Rest框架和Mongoengine.

这是我的模型的样子：

class TestSnapshot(EmbeddedDocument):
    identifier = StringField()
name = StringField()
created = DateTimeField(
    default = datetime.datetime.now)

class Test(Document):
    agreement = ReferenceField(Agreement)
history = ListField(EmbeddedDocumentField(TestSnapshot))
created = DateTimeField(
    default = datetime.datetime.now)

在我看来：

test = models.Test.objects.filter(agreement__in = agreements).aggregate([{
    "$unwind": "$created"
}, {
    "$group": {
    "_id": "$created"
    }
}])
print test

但是我有这样的引用：

OperationFailure: command SON([('aggregate', u 'test'), ('pipeline', [{
    '$match': {
        'agreement': {
            '$in': [ObjectId('558b150a89f4ad3f33ebb8ae')]
        }
    }
    },
    [{
    '$unwind': '$created'
    }, {
    '$group': {
        '_id': '$created'
    }
    }]
]), ('cursor', {})]) on namespace noq.$cmd failed: exception: pipeline element 1 is not an object

我究竟做错了什么？我是mongo的Python新手.
 感谢您的帮助:)

最好的祝福,
强尼

解决方法:

我已经解决了问题,但我做错了.

models.Test.objects.filter(agreement__in = agreements).aggregate(
  {"$group": { "_id": "$created" }}
)

不管怎么说,还是要谢谢你 ：)

标签：mongodb,python,django,mongoengine
来源： https://codeday.me/bug/20191120/2041283.html