c#-注册来自不同类的回调
作者:互联网
对于标准的请求服务器,我使用以下代码将请求与服务进行匹配并处理传入的请求.
服务提供者
public class ServiceProvider
{
public ServiceProvider()
{
Services = new Dictionary<Type, IService>
{
{ typeof(FooRequest), new FooService() },
{ typeof(BarRequest), new BarService() },
};
}
protected void OnRequestReceived(object request)
{
Services[request.GetType()].Process(request);
}
}
FooService
public class FooService : IService
{
public object Process(object request)
{
// Process request
}
}
这就像一种魅力,但我想摆脱每种服务的一种方法(流程).我尝试使用“动作和代表”进行操作,但以某种方式无法完成这种简单的结构.
基本上,我的问题是:如何在需要调用它们时注册另一个类的多个方法/回调并将其存储在字典中?
所需结果(伪代码):
服务提供者
public class ServiceProvider
{
public ServiceProvider()
{
var fooService = new FooService();
var barService = new BarService();
Handlers = new Dictionary<Type, Action>
{
{ typeof(FooRequestA), fooService.ProcessA },
{ typeof(FooRequestB), fooService.ProcessB },
{ typeof(BarRequest), barService.Process },
};
}
protected void ProcessRequest(object request)
{
Handlers[request.GetType()].Invoke(request);
}
}
FooService
public class FooService
{
public object ProcessA(FooRequestA request)
{
// Process request A
}
public object ProcessB(FooRequestB request)
{
// Process request B
}
}
解决方案的改进
使用以下方法,您可以简化重复的请求-服务匹配代码:
public void RegisterHandler<TRequest>(Action<TRequest> function)
{
Handlers.Add(typeof(TRequest), request => function.Invoke((TRequest) request));
}
结果是非常干净的用法:
RegisterHandler<FooRequestA>(request => fooService.ProcessA(request));
解决方法:
这是我能想到的最好的. (同时尽量保持您的要求……可能会有更好的方法来实现您实际想要做的事情).我认为您使用该解决方案会失去一点类型安全性:
FooService
public class FooService
{
public object ProcessA(FooRequestA request)
{
return null;
}
public object ProcessB(FooRequestB request)
{
return null;
}
}
酒吧服务
public class BarService
{
public void Process(BarRequest request)
{ }
}
服务提供者
public class ServiceProvider
{
private readonly Dictionary<Type, Action<object>> Handlers;
public ServiceProvider()
{
var fooService = new FooService();
var barService = new BarService();
Handlers = new Dictionary<Type, Action<object>>
{
{typeof(FooRequestA), request => fooService.ProcessA((FooRequestA)request)},
{typeof(FooRequestB), request => fooService.ProcessB((FooRequestB)request)},
{typeof(BarRequest), request => barService.Process((BarRequest)request)}
};
}
protected void ProcessRequest(object request)
{
Handlers[request.GetType()].Invoke(request);
}
}
由于您无法将方法组(例如fooService.ProcessA)转换为Action,因此您需要将lambda添加到Dictionary< Type,Action< object>并提供请求作为参数.
标签:delegates,func,action,c,net 来源: https://codeday.me/bug/20191119/2033052.html