php-提交表单时,引导程序模式会打开,但是单击“确定”按钮时,它将不起作用

我有一种用php代码更新mysqli数据库的表格.代码很好,当我提交表单时,数据库更新就可以了.但是我想在提交表单之前收到确认引导程序模式.为此,我使用了以下代码.模态在这里打开,但是当单击“确定”按钮时,它不起作用.

<button class="btn btn-danger btn-lg" name="submit" value="submit" type="submit" data-condition="salaryinfo" data-toggle="modal-confirm" data-message="Are you sure?" data-title="Hi you!" data-target="#submit-confirm">Submit</button>         

          </form>
          <!-- Modal -->
<div class="modal fade" id="submit-confirm" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
  <div class="modal-dialog">
    <div class="modal-content">
      <div class="modal-header">
        <button type="button" class="close" data-dismiss="modal"><span aria-hidden="true">&times;</span><span class="sr-only">Close</span></button>
        <h4 class="modal-title"></h4>
      </div>
      <div class="modal-body"></div>
      <div class="modal-footer">
        <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
        <button type="button" class="btn btn-primary" data-confirm="modal">OK</button>
      </div>
    </div>
  </div>
</div>          

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script type="text/javascript" src="js/jquery-1.12.0.min.js"></script>
<script type="text/javascript" src="js/jquery-ui.min.js"></script>

<!-- For modal -->
<script src="js/confirm-bootstrap.js"></script>
<script type="text/javascript">    
function salaryinfo(){
            return true;
        };

    $(document).ready(function(){
        //modal delete confirm
        $('button[data-toggle="modal-confirm"]').click(function(event) {
            event.preventDefault();
            var self = $(this);
            var message = self.data('message');
            var title = self.data('title');
            var target = $(self.data('target'));
            var condition = self.data('condition');
            if( target.length == 1) {
                target.find('.modal-title').html(title);
                target.find('.modal-body').html(message);
                var showModal = true;
                var fn = window[condition];
                if(typeof fn === 'function') {
                    showModal = fn(condition);
                }
                if( showModal ) {
                    target.on('shown.bs.modal', function(e) {
                        target.find('button[data-confirm="modal"]').click(function(e){
                            e.preventDefault();
                            var parentForm = self.closest('form');
                            console.log(parentForm.html());
                            if( parentForm.length == 1 ) {
                                parentForm.submit();
                            }
                        });
                    });
                    target.modal({ show: true });
                };
            };
        });
    });    
    </script>

对工作方式有什么建议吗？

解决方法:

您已经在提交模式之前提交了表单,因为您的按钮具有提交值：

< button class =“ btn btn-danger btn-lg” name =“ submit” value =“ submit” type =“ submit” data-condition =“ salaryinfo” data-toggle =“ modal-confirm” data-message =“你确定吗？” data-title =“嗨,你好！” data-target =“#submit-confirm”> Submit< / button>

因此,只需将带有数据的普通按钮切换到模态即可.

然后在您的模式上单击确认按钮,以具有提交的值.

您还需要在< form> < / form>

标签：bootstrap-modal,php,jquery
来源： https://codeday.me/bug/20191118/2031133.html