PHP-Cryptography：无法使用PKCS1v15填充使用RSA私钥签名

我正在尝试使用SHA1哈希与Python和Cryptography库实现与PHP的openssl_pkey_get_private和openssl_sign等效的功能签名.我已经读过PHP使用PKCS1v15填充,这也是我尝试使用的填充.我的代码是：

from cryptography.hazmat.primitives import hashes
from cryptography.hazmat.primitives.asymmetric import padding
from cryptography.hazmat.primitives.serialization import load_pem_private_key
from cryptography.hazmat.backends import default_backend

pk = open('key.pem', 'rb')
key = load_pem_private_key(pk.read(), password=None, backend=default_backend())
message = b'hello world'
signature = key.sign(
    message,
    padding.PKCS1v15,
    hashes.SHA1()
)

执行此操作将导致：

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-21-ef3db8a6f4a8> in <module>()
      3     message,
      4     padding.PKCS1v15,
----> 5     hashes.SHA1()
      6 )

/home/vagrant/virtualenvs/test/lib/python3.5/site-packages/cryptography/hazmat/backends/openssl/rsa.py in sign(self, data, padding, algorithm)
    613 
    614     def sign(self, data, padding, algorithm):
--> 615         signer = self.signer(padding, algorithm)
    616         signer.update(data)
    617         signature = signer.finalize()

/home/vagrant/virtualenvs/test/lib/python3.5/site-packages/cryptography/hazmat/backends/openssl/rsa.py in signer(self, padding, algorithm)
    550 
    551     def signer(self, padding, algorithm):
--> 552         return _RSASignatureContext(self._backend, self, padding, algorithm)
    553 
    554     def decrypt(self, ciphertext, padding):

/home/vagrant/virtualenvs/test/lib/python3.5/site-packages/cryptography/hazmat/backends/openssl/rsa.py in __init__(self, backend, private_key, padding, algorithm)
    170 
    171         if not isinstance(padding, AsymmetricPadding):
--> 172             raise TypeError("Expected provider of AsymmetricPadding.")
    173 
    174         self._pkey_size = self._backend._lib.EVP_PKEY_size(

TypeError: Expected provider of AsymmetricPadding.

解决方法:

运算符isinstance指示padding.PKCS1v15必须是一个实例,而不是类型(类)本身.这意味着应该通过调用构造函数来创建对象实例.

为此,请添加括号,即padding.PKCS1v15().

标签：pkcs1,cryptography,python,php
来源： https://codeday.me/bug/20191118/2026460.html