php-在jquery中循环循环laravel数组集合

我想使用jquery将选择标签附加到我的代码中,并且它的选项需要laravel数组集合中的值

控制者

$array['skills'] = DB::table('skills')->get();

脚本

 <script type="text/javascript">
    var skill_count=$('#skill_count').val();
    var array = {!!$array['skills']!!};

    $("#add-skill").click(function(){
        skill_count++;            
        var skill='<div class="row skill"><div class="col-sm-4"><label for="name">Skill:</label><select name="skill['+skill_count+'][skill_name]" class="form-control">$.each( array, function( i, val ) {<option value="+ val.id +"> val.skill_name </option>})</select></div><div class="col-sm-4"><label for="name">Experience:</label><select name="skill['+skill_count+'][pivot][experience_year]"   class="form-control">for(i=1;i<=30;i++){<option value="+ i +">i</option>}</select><select name="skill['+skill_count+'][pivot][experience_month]"   class="form-control">for(i=1;i<=12;i++){<option value="+i+">i</option>}</select></div><div class="col-md-12"><a class="skill-remove pull-right">- Remove Skill</a></div></div>'
        $(".show-skill").before(skill);
    });
</script>

但是在浏览器中,val.id和val.skill_name没有获取值.

console.log(val.skill_name);给我价值

解决方法:

希望这会有所帮助

var array =  [{
    id: 2,
    skill_name: 'abc'
}, {
    id: 3,
    skill_name: 'xyz'
}];

var options;
$.each( array, function( key, value ) {
console.log(value.skill_name);
  options = options + '<option value="'+value.id+'">'+value.skill_name+'</option>';
});


var skillhtml = '<div><label for="name">Skill:</label><select name="skillname">'+options+'</select></div>';

$("#container").html(skillhtml);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div id="container">
</div>

jsfiddle：https://jsfiddle.net/j5nkLabw/

标签：laravel-5-4,php,jquery
来源： https://codeday.me/bug/20191111/2019858.html