java-spring数据jpa和多次收集的条件

我想通过所有应该匹配的列表.

  @Query("select g.name as name FROM Gym  g  " +
            "LEFT JOIN g.listOfEquipment   listOfEquipment  " +
            "WHERE " +
            "(((:listOfEquipment) is null) or listOfEquipment.id in (:listOfEquipment)) "+
            "AND (((:listOfAmenity) is null) or listOfAmenity.id in (:listOfAmenity))")
  Page<Map<String, Object>> listing(@Param("listOfEquipment") Set<Integer> listOfEquipment,@Param("listOfAmenity") Set<Integer> listOfAmenity)

以上查询工作为OR,但我需要AND

假设我通过1,2,3
那么结果应该是所有拥有设备1、2和3的体育馆
便利设施也一样

我试过了
Finding items with a set containing all elements of a given set with jpql

但它没有帮助我,因为有多个过滤器

网址为

http://localhost:8080/filter?listOfEquipment=5,3&listOfAmenity=51,13&sort=name

解决方法:

该查询应为您提供匹配所有listOfEquipments的Gym.ids,并假定该列表不包含重复项.

select g.id as name 
FROM Gym  g 
LEFT JOIN g.listOfEquipment listOfEquipment
WHERE listOfEquipment.id in (:listOfEquipment)) 
GROUP BY g.id
HAVING count(g.id) = #{#listOfEquipment.size}    

您可以将它和对listOfAmenity的类似查询用作主查询中的子选择.

select g.name as name 
FROM Gym  g 
LEFT JOIN g.listOfEquipment listOfEquipment 
WHERE (((:listOfEquipment) is null) 
    OR g.id in (
    select g.id as name 
    FROM Gym  g 
    LEFT JOIN g.listOfEquipment listOfEquipment
    WHERE listOfEquipment.id in (:listOfEquipment)) 
    GROUP BY g.id
    HAVING count(g.id) = #{#listOfEquipment.size}   
)) 
AND (((:listOfAmenity) is null) 
    OR g.id in (
    select g.id as name 
    FROM Gym  g 
    LEFT JOIN g.listOfAmenity listOfAmenity
    WHERE listOfAmenity.id in (:listOfAmenity)) 
    GROUP BY g.id
    HAVING count(g.id) = #{#listOfAmenity.size}   
))

标签：postgresql,spring-data-jpa,jpa,spring,java
来源： https://codeday.me/bug/20191110/2014881.html