c#-在步骤函数中将Json字符串传递给AWS Lambda-JsonReaderException错误
作者:互联网
我正在尝试在Step Function中使用AWS Lambda函数.当Lambda函数经过单独测试并且json输入被转义时,它可以正常工作.但是,当输入通过步进函数传递给lambda函数时,我收到了JsonReaderException错误.我究竟做错了什么?社区是否知道解决此问题的方法?
lambda函数:
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Net.Http;
using System.Net.Http.Headers;
using System.Runtime.Serialization.Formatters.Binary;
using Amazon.Lambda.Core;
using Newtonsoft.Json.Linq;
// Assembly attribute to enable the Lambda function's JSON input to be converted into a .NET class.
[assembly: LambdaSerializer(typeof(Amazon.Lambda.Serialization.Json.JsonSerializer))]
namespace AWSLambda1
{
public class Function
{
public void PostsBasedOnOddOrEven(string input, ILambdaContext context)
{
var details = JObject.Parse(input);
var postId = (int) details["id"];
var oddOrEvenResult = (int) details["OddOrEvenPostsResult"];
}
}
}
从Step Function输入到Lambda函数:
{
"id": "1",
"OddOrEvenPostsResult": 2
}
输入Lambda函数(可通过Visual Studio调用):
"{ \"id\": \"1\", \"OddOrEvenPostsResult\": 2}"
异常堆栈跟踪:
{
"errorType": "JsonReaderException",
"errorMessage": "Unexpected character encountered while parsing value: {. Path '', line 1, position 1.",
"stackTrace": [
"at Newtonsoft.Json.JsonTextReader.ReadStringValue(ReadType readType)",
"at Newtonsoft.Json.JsonTextReader.ReadAsString()",
"at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.ReadForType(JsonReader reader, JsonContract contract, Boolean hasConverter)",
"at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.Deserialize(JsonReader reader, Type objectType, Boolean checkAdditionalContent)",
"at Newtonsoft.Json.JsonSerializer.DeserializeInternal(JsonReader reader, Type objectType)",
"at Newtonsoft.Json.JsonSerializer.Deserialize[T](JsonReader reader)",
"at Amazon.Lambda.Serialization.Json.JsonSerializer.Deserialize[T](Stream requestStream)",
"at lambda_method(Closure , Stream , Stream , LambdaContextInternal )"
]
}
Lambda函数作为Step Function的一部分时不起作用
Lambda函数在单独测试时正常工作
解决方法:
由于您的lambda函数期望输入为字符串,因此框架尝试将输入解析为字符串.
但是,输入实际上是JSON对象,而不是字符串.
因此,解析器将失败,并显示“意外字符”错误.解析器期望一个“字符,它将指示字符串的开头.
因此,这是解决方法:
>声明一个代表输入的c#类
public class FunctionInput
{
public int id { get; set; }
public int OddOrEvenPostsResult { get; set; }
}
>更改函数签名,以期望输入FunctionInput类型
public class Function
{
public void PostsBasedOnOddOrEven(FunctionInput input, ILambdaContext context)
{
var postId = input.id;
var oddOrEvenResult = input.OddOrEvenPostsResult;
}
}
注意:您不需要自己解析输入.
标签:net-core,aws-lambda,aws-step-functions,c 来源: https://codeday.me/bug/20191109/2011050.html