php-preg_replace仅外部标签？ (…我们不是在说完整的“ html解析”,只是降价了一点)

在OCCASIONAL标记“< ...>”内的某些文本(不包括文本)加亮的最简单方法是什么？

澄清：我希望保留现有标签！

$t = 
preg_replace(
  "/(markdown)/",
  "<strong>$1</strong>",
"This is essentially plain text apart from a few html tags generated with some
simplified markdown rules: <a href=markdown.html>[see here]</a>");

应显示为：

“这基本上是纯文本,除了一些用某些简化的降价规则生成的html标签：see here”

…但不要在锚标记内添加文本(即< a href = markdown.html>).

我听说过不使用正则表达式解析html的说法,但是在这里,我们实质上是在谈论纯文本,只是对某些markdown代码的最小解析.

解决方法:

实际上,这似乎可以正常工作：

<?php
$item="markdown";
$t="This is essentially plain text apart from a few html tags generated 
with some simplified markdown rules: <a href=markdown.html>[see here]</a>";

//_____1. apply emphasis_____
$t = preg_replace("|($item)|","<strong>$1</strong>",$t);

// "This is essentially plain text apart from a few html tags generated 
// with some simplified <strong>markdown</strong> rules: <a href=
// <strong>markdown</strong>.html>[see here]</a>"

//_____2. remove emphasis if WITHIN opening and closing tag____
$t = preg_replace("|(<[^>]+?)(<strong>($item)</strong>)([^<]+?>)|","$1$3$4",$t);

// this preserves the text before ($1), after ($4) 
// and inside <strong>..</strong> ($2), but without the tags ($3)

// "This is essentially plain text apart from a few html tags generated
// with some simplified <strong>markdown</strong> rules: <a href=markdown.html>
// [see here]</a>"

?>

像$item =“ odd | string”这样的字符串会引起一些问题,但是无论如何我都不会使用这种字符串…(可能需要htmlentities(…)之类的东西…)

标签：markdown,preg-replace,markup,html,php
来源： https://codeday.me/bug/20191105/1995924.html