将xml发布到spring REST端点不会被解组到相关的Java对象中
作者:互联网
我有一个给定xsd的项目.我使用xjc编译器生成Java类.然后,我用XmlRootElement属性注释该类.我已经在AnnotationMethodHandlerAdapter中用Jaxb2编组/解组bean配置了sevlet.当我发送不带名称空间的xml时,出现415错误.
源代码如下
文件-web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>Test</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
文件-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/oxm http://www.springframework.org/schema/oxm/spring-oxm-3.0.xsd"
xmlns:oxm="http://www.springframework.org/schema/oxm">
<context:component-scan base-package="com.test.endpoints" />
<tx:annotation-driven />
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<list>
<ref bean="marshallingHttpMessageConverter"/>
</list>
</property>
</bean>
<bean id="marshallingHttpMessageConverter"
class="org.springframework.http.converter.xml.MarshallingHttpMessageConverter">
<constructor-arg ref="jaxb2Marshaller" />
</bean>
<bean id="jaxb2Marshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshaller">
<property name="classesToBeBound">
<list>
<value>com.test.users.User</value>
<value>com.test.users.Users</value>
</list>
</property>
</bean>
<!-- Should be defined last! -->
<!-- <mvc:annotation-driven />-->
</beans>
文件-user.xsd
<element name="users">
<complexType>
<sequence>
<element name="user" type="tns:user" minOccurs="0"
maxOccurs="unbounded" />
</sequence>
</complexType>
</element>
<complexType name="user">
<sequence>
<element name="id" type="int" />
<element name="email" type="string"></element>
<element name="first_name" type="string"></element>
<element name="last_name" type="string"></element>
</sequence>
</complexType>
</schema>
使用此命令为上述xsd生成Java类.
xjc -p com.test.users ..\xsd\user.xsd
该命令的输出是
parsing a schema...
compiling a schema...
com\test\users\ObjectFactory.java
com\test\users\User.java
com\test\users\Users.java
com\test\users\package-info.java
用@XmlRootElement(name =“ user”)注释的User.java.
文件-UserService.java
package com.test.endpoints;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import com.test.users.User;
@Controller
@RequestMapping("/users")
public class UserService {
@RequestMapping(value="/new", method=RequestMethod.POST)
@ResponseBody
public User createUser(@RequestBody User user) {
System.out.println(user.getFirstName());
return user;
}
}
使用curl命令测试了REST API
curl -X POST -HContent-type:application/xml -HAccept:application/xml --data "<?xml version="1.0" encoding="UTF-8"?><user><id>1</id><email>email@email.com</email><first_name>first_name</first_name><last_name>last_name</last_name></user>" http://localhost:8080/Test/rest/users/new
输出是
The request sent by the client was syntactically incorrect ()
有人可以指出我要去哪里.
谢谢
解决方法:
我也遇到了同样的问题.这是我的Controller方法的样子:
@RequestMapping(method=RequestMethod.POST, value="/users/create",
headers="Accept=application/xml")
public @ResponseBody User createUser(@RequestBody User user) {
return user;
}
基本上,我只是返回用户对象作为概念验证,以确保POST正常工作.但是,我一直遇到“语法错误”的消息.实际更新代码以检索有效的User对象后,如下所示:
@RequestMapping(method=RequestMethod.POST, value="/users/create",
headers="Accept=application/xml")
public @ResponseBody User createUser(@RequestBody User user) {
userService.createUser(user);
// do work
User newUser = userService.getUserById(user.getId());
return newUser;
}
它开始正常工作.
我使用以下CURL命令测试了REST API:
curl -X POST -HContent-type:application/xml -HAccept:application/xml --data "<user><username>Quinnster</username><password>password</password></user>" http://localhost:8080/api/users/create
使用不同的API列出用户,我能够验证我的新用户是否正确创建.
同样,不确定这是否与您遇到的问题完全相同,但这为我解决了这一问题.
谢谢,
奎因
标签:jaxb2,jaxb,model-view-controller,spring,java 来源: https://codeday.me/bug/20191102/1994393.html