鼠标滚轮python curses

有谁知道是否有可能以诅咒来处理鼠标滚轮的运动？我想它们应该与箭头键相同.一个例子将不胜感激.

谢谢.

解决方法:

我猜这是系统和终端相关的.我写了以下内容-它只捕获鼠标状态并将其打印到屏幕上.我可以使用xterm在Mac OSX中接收鼠标滚动事件. (对我来说向上滚动注册为按钮4；向下滚动为按钮2,但使用本机Terminal应用程序无法正常工作.)

如果您查看此代码,将很清楚,您必须首先使用scr.getch(),然后测试它是否返回curses.KEY_MOUSE.如果是这样,则可以调用curses.getmouse(),这将返回一个包含设备ID,坐标和状态标志的元组.

import curses
from contextlib import contextmanager

@contextmanager
def open_screen():
    scr = curses.initscr()
    curses.noecho()
    curses.cbreak()
    scr.keypad(1)
    try:
        yield scr
    finally:
        curses.nocbreak()
        scr.keypad(0)
        curses.echo()
        curses.endwin()

curses_mouse_states = {
    curses.BUTTON1_PRESSED: 'Button 1 Pressed', 
    curses.BUTTON1_RELEASED: 'Button 1 Released', 
    curses.BUTTON1_CLICKED: 'Button 1 Clicked',
    curses.BUTTON1_DOUBLE_CLICKED: 'Button 1 Double-Clicked',
    curses.BUTTON1_TRIPLE_CLICKED: 'Button 1 Triple-Clicked',

    curses.BUTTON2_PRESSED: 'Button 2 Pressed', 
    curses.BUTTON2_RELEASED: 'Button 2 Released', 
    curses.BUTTON2_CLICKED: 'Button 2 Clicked',
    curses.BUTTON2_DOUBLE_CLICKED: 'Button 2 Double-Clicked',
    curses.BUTTON2_TRIPLE_CLICKED: 'Button 2 Triple-Clicked',

    curses.BUTTON3_PRESSED: 'Button 3 Pressed', 
    curses.BUTTON3_RELEASED: 'Button 3 Released', 
    curses.BUTTON3_CLICKED: 'Button 3 Clicked',
    curses.BUTTON3_DOUBLE_CLICKED: 'Button 3 Double-Clicked',
    curses.BUTTON3_TRIPLE_CLICKED: 'Button 3 Triple-Clicked',

    curses.BUTTON4_PRESSED: 'Button 4 Pressed', 
    curses.BUTTON4_RELEASED: 'Button 4 Released', 
    curses.BUTTON4_CLICKED: 'Button 4 Clicked',
    curses.BUTTON4_DOUBLE_CLICKED: 'Button 4 Double-Clicked',
    curses.BUTTON4_TRIPLE_CLICKED: 'Button 4 Triple-Clicked',

    curses.BUTTON_SHIFT: 'Button Shift', 
    curses.BUTTON_CTRL: 'Button Ctrl', 
    curses.BUTTON_ALT: 'Button Alt'
}

with open_screen() as scr:
    curses.mousemask(-1)
    while True:
        c = scr.getch()
        if c == curses.KEY_MOUSE:
            mouse_state = curses.getmouse()[4]
            states = '; '.join(state_string for state, state_string 
                               in curses_mouse_states.viewitems() 
                               if mouse_state & state)
            scr.addstr(0, 0, states)
            scr.clrtoeol()
            scr.refresh()
        elif c == ord('q'):
            break

标签：mousewheel,curses,python
来源： https://codeday.me/bug/20191101/1980188.html