c#-如果接口位于不同的程序集中,则SimpleIoc.Default.Register在IsInDesignModeStatic处失败

在ViewModelLocator类的静态构造函数中,SimpleIoc.Default.Register< T>();如果接口在其他项目中,则在IsInDesignModeStatic模式下失败.结果,MainWindow.xaml设计器在设计时为空.

我提出了一个简单的解决方案进行测试.我所做的唯一更改是将DataItem类和IDataService接口移到Domain项目中.

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我找到了一种解决方法：在ClientWpf项目中添加指向IDataService.cs的链接.

public class ViewModelLocator {
    static ViewModelLocator() {
        ServiceLocator.SetLocatorProvider(() => SimpleIoc.Default);

        if (ViewModelBase.IsInDesignModeStatic) {

            // It fails if the IDataService is in different assembly
            // Delete the link of IDataService.cs from the ViewModel folder...
            SimpleIoc.Default.Register<IDataService, Design.DesignDataService>();
        }
        else {
            SimpleIoc.Default.Register<IDataService, DataService>();
        }

        SimpleIoc.Default.Register<MainViewModel>();
    }
...
}

解决方法:

    if (ViewModelBase.IsInDesignModeStatic) {


        // put these lines here:
        if (SimpleIoc.Default.IsRegistered<IDataService>()) {
            SimpleIoc.Default.Unregister<IDataService>();
        }

        SimpleIoc.Default.Register<IDataService, Design.DesignDataService>();
    }
    else {
        SimpleIoc.Default.Register<IDataService, DataService>();
    }

标签：mvvm-light,c
来源： https://codeday.me/bug/20191031/1977752.html