Java-Google Charts API JSON无效

以下代码为Google图表返回json

public static DataTable generateDataTable(){
        // Create a data table,
        DataTable data = new DataTable();
        ArrayList cd = new ArrayList();
        cd.add(new ColumnDescription("name", ValueType.TEXT, "Animal name"));
        cd.add(new ColumnDescription("link", ValueType.TEXT, "Link to wikipedia"));
        cd.add(new ColumnDescription("population", ValueType.NUMBER, "Population size"));
        cd.add(new ColumnDescription("vegeterian", ValueType.BOOLEAN, "Vegetarian?"));

        data.addColumns(cd);

        // Fill the data table.
        try {
          data.addRowFromValues("Aye-aye", "http://en.wikipedia.org/wiki/Aye-aye", 100, true);
          data.addRowFromValues("Sloth", "http://en.wikipedia.org/wiki/Sloth", 300, true);
          data.addRowFromValues("Leopard", "http://en.wikipedia.org/wiki/Leopard", 50, false);
          data.addRowFromValues("Tiger", "http://en.wikipedia.org/wiki/Tiger", 80, false);
        } catch (TypeMismatchException e) {
          System.out.println("Invalid type!");
        }


        return data;
}

public static void main(String []args){
    String json = JsonRenderer.renderDataTable(generateDataTable(), false, false).toString();
    System.out.println(json);
}

但是返回的JSON

{cols:[{id:'name',label:'Animal name',type:'string',pattern:''},{id:'link',label:'Link to wikipedia',type:'string',pattern:''},{id:'population',label:'Population size',type:'number',pattern:''},{id:'vegeterian',label:'Vegetarian?',type:'boolean',pattern:''}]}

粘贴到http://jsonlint.com/时无效

另外,返回的json {id：’name’,label：’Animal name’,type：’string’,** pattern：”**}中显示的模式值是什么？

解决方法:

Google向您发送的是JavaScript对象,而不是JSON.

您需要找出一种将JavaScript对象字符串化为JSON的方法.

看看this问题的答案.它可能会帮助您.

标签：google-visualization,json,java
来源： https://codeday.me/bug/20191030/1970102.html