python-可编辑QTableView中的熊猫df:删除复选框
作者:互联网
我有一个熊猫数据框,希望在QtableView中呈现并使其可编辑.我已经创建了以下模型,但是由于某种原因,输出在每个字段中都有复选框.我该如何摆脱它们?
这是用于制作qtavleview中显示的熊猫数据框并使其可编辑的模型(我正在使用PySide)
class PandasModelEditable(QtCore.QAbstractTableModel):
def __init__(self, data, parent=None):
QtCore.QAbstractTableModel.__init__(self, parent)
self._data = data
def rowCount(self, parent=None):
return len(self._data.values)
def columnCount(self, parent=None):
return self._data.columns.size
def data(self, index, role=QtCore.Qt.DisplayRole):
if index.isValid():
if role == QtCore.Qt.DisplayRole or role == QtCore.Qt.EditRole:
return unicode(self._data.iloc[index.row(), index.column()])
return unicode()
def headerData(self, section, orientation, role=QtCore.Qt.DisplayRole):
if role != QtCore.Qt.DisplayRole:
return None
if orientation == QtCore.Qt.Horizontal:
try:
return '%s' % unicode(self._data.columns.tolist()[section])
except (IndexError,):
return unicode()
elif orientation == QtCore.Qt.Vertical:
try:
return '%s' % unicode(self._data.index.tolist()[section])
except (IndexError,):
return unicode()
def flags(self, index):
return QtCore.Qt.ItemIsEnabled | QtCore.Qt.ItemIsSelectable | \
QtCore.Qt.ItemIsEditable
def setData(self, index, value, role=QtCore.Qt.EditRole):
if index.isValid():
self._data.iloc[index.row(), index.column()] = value
if self.data(index, QtCore.Qt.DisplayRole) == value:
self.dataChanged.emit(index, index)
return True
return unicode()
删除QtCore.Qt.ItemIsSelectable不能解决问题,因为它似乎没有任何效果.
解决方法:
您从data和setaData返回了错误的默认值.前者应返回None(因此您可以删除最后一行),而后者应返回False.
标签:qtableview,pandas,pyside,python,model 来源: https://codeday.me/bug/20191026/1936390.html