python-熊猫-按多列分组的移动平均线
作者：互联网
对Pandas来说是新手,所以请耐心等待.
我的数据框的格式为
date,name,country,tag,cat,score
2017-05-21,X,US,free,4,0.0573
2017-05-22,X,US,free,4,0.0626
2017-05-23,X,US,free,4,0.0584
2017-05-24,X,US,free,4,0.0563
2017-05-21,X,MX,free,4,0.0537
2017-05-22,X,MX,free,4,0.0640
2017-05-23,X,MX,free,4,0.0648
2017-05-24,X,MX,free,4,0.0668
我正在尝试找到一种在国家/标签/类别组中查找X天移动平均线的方法,因此我需要：
date,name,country,tag,cat,score,moving_average
2017-05-21,X,US,free,4,0.0573,0
2017-05-22,X,US,free,4,0.0626,0.0605
2017-05-23,X,US,free,4,0.0584,0.0594
2017-05-24,X,US,free,4,0.0563,and so on
...
2017-05-21,X,MX,free,4,0.0537,and so on
2017-05-22,X,MX,free,4,0.0640,and so on
2017-05-23,X,MX,free,4,0.0648,and so on
2017-05-24,X,MX,free,4,0.0668,and so on
我尝试根据需要的列对行进行分组,然后使用pd.rolling_mean,但最后得到了一堆NaN
df.groupby(['date', 'name', 'country', 'tag'])['score'].apply(pd.rolling_mean, 2, min_periods=2) # window size 2
我将如何正确执行此操作？
解决方法:
IIUC：
(df.assign(moving_score=df.groupby(['name','country','tag'], as_index=False)[['score']]
.rolling(2, min_periods=2).mean().fillna(0)
.reset_index(0, drop=True)))
输出：
date name country tag cat score moving_score
0 2017-05-21 X US free 4 0.0573 0.00000
1 2017-05-22 X US free 4 0.0626 0.05995
2 2017-05-23 X US free 4 0.0584 0.06050
3 2017-05-24 X US free 4 0.0563 0.05735
4 2017-05-21 X MX free 4 0.0537 0.00000
5 2017-05-22 X MX free 4 0.0640 0.05885
6 2017-05-23 X MX free 4 0.0648 0.06440
7 2017-05-24 X MX free 4 0.0668 0.06580
标签：moving-average,pandas,python 来源： https://codeday.me/bug/20191025/1930443.html