java-如何将两个Kafka流结合在一起,并在具有Avro值的主题中产生结果
作者:互联网
我有两个Kafka Streams,它们具有String键和我使用KSQL创建的Avro格式的值.
这是第一个:
DESCRIBE EXTENDED STREAM_1;
Type : STREAM
Key field : IDUSER
Timestamp field : Not set - using <ROWTIME>
Key format : STRING
Value format : AVRO
Kafka output topic : STREAM_1 (partitions: 4, replication: 1)
Field | Type
--------------------------------------------------------
ROWTIME | BIGINT (system)
ROWKEY | VARCHAR(STRING) (system)
FIRSTNAME | VARCHAR(STRING)
LASTNAME | VARCHAR(STRING)
IDUSER | VARCHAR(STRING)
第二个:
DESCRIBE EXTENDED STREAM_2;
Type : STREAM
Key field : IDUSER
Timestamp field : Not set - using <ROWTIME>
Key format : STRING
Value format : AVRO
Kafka output topic : STREAM_2 (partitions: 4, replication: 1)
Field | Type
--------------------------------------------------------
ROWTIME | BIGINT (system)
ROWKEY | VARCHAR(STRING) (system)
USERNAME | VARCHAR(STRING)
IDUSER | VARCHAR(STRING)
DEVICE | VARCHAR(STRING)
所需的输出应包括IDUSER,LASTNAME,DEVICE和USERNAME.
我想使用Streams API离开(在IDUSER上)加入这些流,并将输出写入kafka主题.
为此,我尝试了以下方法:
public static void main(String[] args) {
final Properties streamsConfiguration = new Properties();
streamsConfiguration.put(StreamsConfig.APPLICATION_ID_CONFIG, "kafka-strteams");
streamsConfiguration.put(StreamsConfig.BOOTSTRAP_SERVERS_CONFIG, "localhost:9092");
streamsConfiguration.put(StreamsConfig.ZOOKEEPER_CONNECT_CONFIG, "localhost:2181");
streamsConfiguration.put(AbstractKafkaAvroSerDeConfig.SCHEMA_REGISTRY_URL_CONFIG, "http://localhost:8081");
streamsConfiguration.put(StreamsConfig.KEY_SERDE_CLASS_CONFIG, Serdes.String().getClass().getName());
streamsConfiguration.put(StreamsConfig.VALUE_SERDE_CLASS_CONFIG, GenericAvroSerde.class);
streamsConfiguration.put(ConsumerConfig.AUTO_OFFSET_RESET_CONFIG, "earliest");
final Serde<String> stringSerde = Serdes.String();
final Serde<GenericRecord> genericAvroSerde = new GenericAvroSerde();
boolean isKeySerde = false;
genericAvroSerde.configure(Collections.singletonMap(AbstractKafkaAvroSerDeConfig.SCHEMA_REGISTRY_URL_CONFIG, "http://localhost:8081"), isKeySerde);
KStreamBuilder builder = new KStreamBuilder();
KStream<String, GenericRecord> left = builder.stream("STREAM_1");
KStream<String, GenericRecord> right = builder.stram("STREAM_2");
// Java 8+ example, using lambda expressions
KStream<String, GenericRecord> joined = left.leftJoin(right,
(leftValue, rightValue) -> "left=" + leftValue + ", right=" + rightValue, /* ValueJoiner */
JoinWindows.of(TimeUnit.MINUTES.toMillis(5)),
Joined.with(
stringSerde, /* key */
genericAvroSerde, /* left value */
genericAvroSerde) /* right value */
);
joined.to(stringSerde, genericAvroSerde, "streams-output-testing");
KafkaStreams streams = new KafkaStreams(builder, streamsConfiguration);
streams.cleanUp();
streams.start();
Runtime.getRuntime().addShutdownHook(new Thread(streams::close));
}
然而,
KStream<String, GenericRecord> joined = ...
在我的IDE上抛出错误:
incompatible types: inference variable VR has incompatible bounds
当我尝试将String Serde用作键和值时,它可以工作,但数据不能从kafka-console-consumer读取.我要做的是以AVRO格式生成数据,以便能够使用kafka-avro-console-consumer读取它们.
解决方法:
我的第一个猜测是您要从join操作返回一个String,而您的代码期望将GenericRecord作为结果:
KStream<String, GenericRecord> joined = left.leftJoin(right,
(leftValue, rightValue) -> "left=" + leftValue + ", right=" + rightValue, ...)
请注意,联接的类型为KStream< String,GenericRecord> ;,即值的类型为GenericRecord,但是联接输出是通过类型为String的“ left =“ leftValue”,right =“ rightValue计算的.
标签:apache-kafka-streams,apache-kafka,ksql,java 来源: https://codeday.me/bug/20191025/1926724.html