java-自定义功能接口作为方法参数

我下面的代码确实产生预期的结果.有人可以解释幕后发生的事情吗？我不明白编译器/ JVM如何知道需要在Storer对象上调用store(String str)或如何定义doSomething(Storer s,String str)实现.

Storer.java

public class Storer {
    private List<String> storer = new ArrayList<>();

    public void store(String str) {
        storer.add(str);
    }

    @Override
    public String toString() {
        return "Storer [storer=" + storer + "]";
    }

}

MyInterface.java

@FunctionalInterface
public interface MyInterface {
    public abstract void doSomething(Storer s, String str);
}

执行程序

public class Executor {
    public void doStore(Storer storer, String s, MyInterface p) {
        p.doSomething(storer, s);
    }
}

TestFunctionalInterfaces.java

public class TestFunctionalInterfaces {
    public static void main(String[] args) {
        Storer storer = new Storer();

        Executor test = new Executor();
        test.doStore(storer, "I've got added", Storer::store);

        System.out.println(storer);
    }
}

输出为：

Storer [storer=[I've got added]]

提前致谢.

解决方法:

方法参考Store :: storer等效于lambda(s,str)->商店(str).通常,给定一个期望参数为a1,a2,a3,…的功能接口,此类型的方法引用等效于调用a1.namedMethod(a2,a3,…)的lambda.参见this answer.

标签：functional-interface,java
来源： https://codeday.me/bug/20191024/1922998.html