javascript-使用带延误的runSaga测试
作者:互联网
如果我有这样的传奇故事:
function * sagaWorker() {
yield put(START_ACTION)
yield take(WAIT_FOR_ACTION)
yield delay(100)
yield put(END_ACTION)
}
我可以像这样使用runSaga成功测试它:
step('saga passes the tests', async () => {
const channel = stdChannel()
const dispatched = []
const options = {
dispatch: action => dispatched.push(action),
getState: () => {},
channel
}
const task = runSaga(options, sagaWorker)
channel.put(WAIT_FOR_ACTION)
await task.toPromise()
expect(dispatched).to.deep.eql([START_ACTION, END_ACTION])
})
但是,如果我将延迟转移到汇票的前面:
function * sagaWorker() {
yield put(START_ACTION)
yield delay(100)
yield take(WAIT_FOR_ACTION)
yield put(END_ACTION)
}
现在,传奇故事并没有完成并超时-可以接受,但动作从未到达频道.
是否可以使用此表格进行测试?我怀疑我可以通过调用延迟而不是直接产生延迟来使其工作,但是我想知道如何在不这样做的情况下使其工作(如果可能的话).
解决方法:
使用yield call(()=> myPromiseyDelay(500))不会在这里保存您.派发时仍然没有什么可以注意到“丢失”的动作.
当您发布WAIT_FOR_ACTION时,由于收益延迟,传奇故事处于收益状态.这里没有行动的队列,因此,在您放弃屈服(WAIT_FOR_ACTION)时,WAIT_FOR_ACTION行动早已被分派,而您上面提出的任何佐贺逻辑都没有注意到(没有采取行动的主动行动) ).
考虑设置一个actionChannel
来捕获这些未侦听的动作.延迟结束后,它们将在通道中排队等待使用.
因此,类似:
function * sagaWorker() {
const channel = yield actionChannel(WAIT_FOR_ACTION)
yield put(START_ACTION)
yield delay(100)
yield take(channel)
yield put(END_ACTION)
}
因此,将所有内容组合为非伪代码:
const {
runSaga,
stdChannel,
effects: {
take,
put,
actionChannel,
delay
}
} = window.ReduxSaga
const WAIT_FOR_ACTION = "WAIT_FOR_ACTION";
const START_ACTION = "START_ACTION";
const END_ACTION = "END_ACTION";
(async() => {
const channel = stdChannel();
const dispatched = [];
const options = {
dispatch: action => dispatched.push(action),
getState: () => {},
channel
};
const task = runSaga(options, sagaWorker);
channel.put({
type: WAIT_FOR_ACTION
});
await task.toPromise();
console.log(dispatched);
})();
function* sagaWorker() {
const channel = yield actionChannel(WAIT_FOR_ACTION);
yield put({
type: START_ACTION
});
yield delay(100);
yield take(channel);
yield put({
type: END_ACTION
});
}
<script src="https://cdn.jsdelivr.net/npm/redux-saga@1.0.2/dist/redux-saga.umd.min.js"></script>
标签:redux-saga,redux,javascript 来源: https://codeday.me/bug/20191024/1922382.html