java-如何检查日期时间是使用Joda Time重复发生的事件?
作者:互联网
我有一个DateTime,表示重复事件的开始.天(每日周期)将代表重复周期.我认为这个重复发生的事件将永远不会停止.
from = "2013-06-27"
period = 3 days
nextOccurence will be "2013-06-30", "2013-07-03", "2013-07-06", and so on.
"2013-07-03" is an occurence but "2013-07-04" isn't an occurence.
我想知道在性能方面确定DateTime是否发生重复事件的最佳方法是什么?从长远来看,该程序将需要检查是否出现了“ 2014-07-03”或“ 2015-07-03”.
解决方法:
这将在我的计算机上在180毫秒的时间内运行所有五次检查.大约每秒27次检查,即您要检查未来300年的日期.
@Test
public void isOccurrence() {
long startTime = System.currentTimeMillis();
assertTrue(isOccurrence(new DateMidnight(2010, 1, 10), 3, new DateTime(2010, 1, 19, 0, 0)));
assertFalse(isOccurrence(new DateMidnight(2010, 1, 10), 3, new DateTime(2010, 1, 18, 0, 0)));
assertTrue(isOccurrence(new DateMidnight(2010, 1, 10), 3, new DateTime(2310, 1, 19, 0, 0)));
assertFalse(isOccurrence(new DateMidnight(2010, 1, 10), 3, new DateTime(2310, 1, 20, 0, 0)));
assertTrue(isOccurrence(new DateMidnight(2010, 1, 10), 3, new DateTime(2010, 1, 10, 0, 0)));
System.out.println("elapsed=" + (System.currentTimeMillis() - startTime));
}
public boolean isOccurrence(DateMidnight startDate, int dayIncrement, DateTime testTime) {
DateMidnight testDateMidnight = testTime.toDateMidnight();
while (startDate.isBefore(testDateMidnight)) {
startDate = startDate.plusDays(dayIncrement);
}
return startDate.equals(testDateMidnight);
}
标签:java,performance,jodatime,time 来源: https://codeday.me/bug/20191013/1907184.html