为什么函数对象在python中评估为True？

在python中进行如下构造是有效的：

def a(): 
    return 0

if a: 
    print "Function object was considered True"
else:  
    print "Function object was considered False"

我想问一个函数指针被评估为True的逻辑是什么.

为什么在语言中插入这种构造？

解决方法:

在Python中,很多东西都评估为True.从documentation on Boolean operators：

In the context of Boolean operations, and also when expressions are used by control flow statements, the following values are interpreted as false: False, None, numeric zero of all types, and empty strings and containers (including strings, tuples, lists, dictionaries, sets and frozensets). All other values are interpreted as true.

Python中的函数就像很多东西一样,都是对象,而不是空的.因此,在布尔上下文中,它们的值为True.

标签：python,function,function-pointers
来源： https://codeday.me/bug/20191013/1904626.html