使用Python将Json转换为CSV

下面是我从在线气象站提取的json结构.我还包括一个json_to_csv python脚本,该脚本应该将json数据转换为csv输出,但仅返回“ Key”错误.我只想从“ current_observation”中提取数据.

{
  "response": {
  "features": {
  "conditions": 1
  }
    }
  , "current_observation": {
        "display_location": {
        "latitude":"40.466442",
        "longitude":"-85.362709",
        "elevation":"280.4"
        },
        "observation_time_rfc822":"Fri, 26 Jan 2018 09:40:16 -0500",
        "local_time_rfc822":"Sun, 28 Jan 2018 11:22:47 -0500",
        "local_epoch":"1517156567",
        "local_tz_short":"EST",
        "weather":"Clear",
        "temperature_string":"44.6 F (7.0 C)",
    }
}



import csv, json, sys
inputFile = open("pywu.cache.json", 'r') #open json file
outputFile = open("CurrentObs.csv", 'w') #load csv file
data = json.load(inputFile) #load json content 
inputFile.close() #close the input file
output = csv.writer(outputFile) #create a csv.write
output.writerow(data[0].keys())
for row in data:
    output = csv.writer(outputFile) #create a csv.write 
    output.writerow(data[0].keys())
for row in data:
    output.writerow(row.values()) #values row

检索温度字符串并将其转换为.csv格式的最佳方法是什么？谢谢！

解决方法:

import pandas as pd
df = pd.read_json("pywu.cache.json")
df = df.loc[["local_time_rfc822", "weather", "temperature_string"],"current_observation"].T
df.to_csv("pywu.cache.csv")

也许熊猫可以为您提供帮助. .read_json()函数创建一个不错的数据框,您可以从中轻松选择所需的行和列.它也可以另存为csv.

要将纬度和经度添加到csv行中,您可以执行以下操作：

df = pd.read_json("pywu.cache.csv")
df = df.loc[["local_time_rfc822", "weather", "temperature_string", "display_location"],"current_observation"].T
df = df.append(pd.Series([df["display_location"]["latitude"], df["display_location"]["longitude"]], index=["latitude", "longitude"]))
df = df.drop("display_location")
df.to_csv("pywu.cache.csv")

要以数字值打印位置,可以执行以下操作：

df = pd.to_numeric(df, errors="ignore")
print(df['latitude'], df['longitude'])

标签：export-to-csv,python
来源： https://codeday.me/bug/20191009/1881215.html