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python-如何检查网页的弹出窗口?

作者:互联网

如果我用python编写的程序允许使用mechanizeautomatically browse a given website来检测是否存在使用Python的弹出窗口(建议广告或下载操作…),是否有可能?我将不胜感激(例如,如果您给我一个可以完成此任务的图书馆,我将非常高兴)

解决方法:

机械化无法处理javascript和弹出窗口:

> How do I use Mechanize to process JavaScript?
> Mechanize and Javascript

要实现该目标,您需要使用一个真实的浏览器,无论是否使用headless.这是selenium可以提供帮助的地方.它具有built-in support for popup dialogs

Selenium WebDriver has built-in support for handling popup dialog
boxes. After you’ve triggerd and action that would open a popup, you
can access the alert with the following:

alert = driver.switch_to_alert()

示例(使用此jsfiddle):

from selenium import webdriver

url = "http://fiddle.jshell.net/ebkXh/show/"
driver = webdriver.Firefox()
driver.get(url)

button = driver.find_element_by_xpath('//button[@type="submit"]')

# dismiss
button.click()
driver.switch_to.alert.dismiss()

# accept
button.click()
driver.switch_to.alert.accept()

也可以看看:

> Handle Popup Windows
> Click the javascript popup through webdriver

标签:python,firefox,popup,webpage,mechanize
来源: https://codeday.me/bug/20191009/1877851.html