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javascript – CasperJs,如何在WaitTimeout上重复一次X步?

作者:互联网

所以我想要做的是创建一个casperJS函数,它允许我们重复一个步骤X次,首先刷新页面,当这个步骤函数达到超时时.

对于由于特定页面错误/冻结而导致的不可靠测试,并减少假阴性的百分比.

我只是一个问题,我不知道如何打破这个循环,因为我在IIFE范围内,请看下面的代码:

var echoTest = function(){
    casper.echo('Hi');
};
var trueFunction = function(){
    return true;
};

var verifyFailedTest = function(number, trueReturn, thenFunction){
    var i = 0;
    //outer:       <-------
    for (; i <= number; i++){   // <------ how to break this loop in my function then()
        //IIFE
        (function(index){
            if (index < number-1){
                //Execute 'number-1' times the then() step (reload the page each time) if timeout or until trueReturn returns true
                casper.then(function(){
                    casper.waitFor(function checkReturnTrue(){
                            return trueReturn();
                        }
                        , function then() {
                            thenFunction();
                            //break outer; break; return false;    <------ here where I want to break the loop
                        }
                        , function timeout() { 
                            casper.reload();
                        });
                });
            }
            //last execution, will return the normal error if it fails each time
            else if (index === number){
                casper.then(function(){
                    casper.waitFor(function checkReturnTrue(){
                            return trueReturn();
                        }
                        , function then() {
                            console.log('else');
                            thenFunction();
                        });
                });
            }
            else{console.log('verifyFailedTest() bug');}
        })(i);
    }
};

我尝试使用label,但是我遇到了语法错误.

执行:

casper.test.begin('\n*************** Suite of planned test : scenario 1 **************\n', 1, function suite(test) {
    casper.start('https://www.google.fr/', function() {
        verifyFailedTest(3, trueFunction, echoTest);
    });

    casper.run(function() {
        test.done();
    });
});

});

解决方法:

我认为可以在没有for循环的情况下通过将代码聚类成部分并以递归方式执行此操作:

var verifyFailedTest = function(number, repeatStep, trueReturn){
    var index = 0;
    function intermediate(){
        casper.then(function(){
            repeatStep();
            casper.waitFor(function checkReturnTrue(){
                    return trueReturn();
                }
                , function then() {
                    this.test.pass("Test passes after " + (index+1) + " try");
                }
                , function timeout() { 
                    casper.reload();
                    if (index < number-1) {
                        intermediate();
                    } else {
                        lastTry();
                    }
                    index++;
                });
        });
    }
    function lastTry(){
        casper.then(function(){
            repeatStep();
            casper.waitFor(function checkReturnTrue(){
                    return trueReturn();
                }
                , function then() {
                    this.test.pass("Test passes after " + (index+1) + " try");
                });
        });
    }
    intermediate();
};

只有在尝试次数后才会出现错误.

但是如果你想使用你的IIFE,以下可能会通过重新定义thenFunction并跳过然后阻止你知道它是不必要的(doBreak === true):

var verifyFailedTest = function(number, trueReturn, thenFunction){
    var i = 0, doBreak = false;
    var oldThenFunction = thenFunction;
    thenFunction = function(){
        doBreak = true;
        oldThenFunction();
    };
    for (; i <= number; i++){
        if (doBreak) {
            break;
        }
        // your IIFE here
        (function(index){
            if (index < number-1){
                //Execute 'number-1' times the then() step (reload the page each time) if timeout or until trueReturn returns true
                casper.then(function(){
                    if (doBreak) { return; }
                    casper.waitFor(...);
                });
            }
            //last execution, will return the normal error if it fails each time
            else if (index === number){
                casper.then(function(){
                    if (doBreak) { return; }
                    casper.waitFor(...);
                });
            }
            else{console.log('verifyFailedTest() bug');}
        })(i);
    }
};

标签:javascript,for-loop,closures,break,casperjs
来源: https://codeday.me/bug/20191007/1868096.html