javascript – 如何修复jslint’\u0026\u0026’子表达式应该包含在parens错误中
作者:互联网
我把所有内容放在括号中但是下面的代码仍然在jslint中抛出错误:
Problem at line 5 character 104: The '&&' subexpression should be wrapped in parens.
if ((typeof (c1) === 'string') && (typeof (c2) === 'string') && (c1 !== n...
怎么修 ?
"use strict";
function t() {
var c1, c2;
if (((typeof (c1)) === 'string') && ((typeof (c2)) === 'string') && (c1 !== null) && (c2 !== null) && ((c1.trim()) === '') || ((c2.trim()) !== '')) {
return;
}
}
解决方法:
它抱怨表格if(a&& b& c || d)因为(我想)并不是很明显是否&&或||将优先考虑.将其修改为如果(a&& b&&(c || d))并且它将停止抱怨.
标签:javascript,jslint 来源: https://codeday.me/bug/20191006/1862873.html